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3 years ago

Rupees500 for 3years at 5 percent?

Mathematics

1 answer:

Naya [18.7K]3 years ago

6 0

What's the question?

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The area of triangle

adoni [48]

The area of a triangle is area=1/2•base•height or a= b•h / 2

8 0

3 years ago

Please help!

Vlada [557]

Option 3: $2^{\frac{5}{6}}$ is the right answer

Step-by-step explanation:

Given expression is:

$(\sqrt{2})(\sqrt[3]{2} )$

In order to simplify the expression we have to convert the radicals in exponents

$2^{\frac{1}{2}} . 2^{\frac{1}{3}}$

As he base is same, the powers can be added

$=2^{\frac{3+2}{6}}\\=2^{\frac{5}{6}}$

Hence,

Option 3: $2^{\frac{5}{6}}$ is the right answer

Keywords: Exponents, radicals

Learn more about exponents at:

#LearnwithBrainly

6 0

3 years ago

In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH

solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)

Consider triangles CBH and BCK. In these triangles,

∠CBH ≅ ∠BCK (from equality (*));
∠HCB ≅ ∠KBC, because m∠B = m∠C;
BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0

3 years ago

Simplify the expression. 2³ times 2^5 A. 4^15 B. 4^8 C. 2^15 D. 2^8

Luden [163]

$(x^m)(x^n)=x^{m+n}$
so
$(2^3)(2^5)=2^{3+5}=2^{8}$
D is answer

7 0

3 years ago

Read 2 more answers

39.2 is what percent if p of 112

crimeas [40]

Answer:

35%%%%%%%%%%%%%%%%%%%%

Step-by-step explanation:

6 0

3 years ago

Rupees500 for 3years at 5 percent?​

Rupees500 for 3years at 5 percent?