4c+3=15
You need to get rid of the 3
So you minus it from each side so you
4c=12
12/4=3
So c =3
Answer: I need a picture off the pool and measurements.
Step-by-step explanation: I need this in order to figure out the problem and give you a helpful answer.
<span>Let t
= travel time at 58</span>
<span>and
(6-t) = travel time at 49
distance at 58 + distance at 49 = 325.5 mi</span>
<span>
58t + 49(6-t) = 325.5
58t + 294 - 49t = 325.5</span>
9t+294
= 325.5
9t
=31.5
T =
31.5/9 = 3.5 hours at 58 mph
6-3.5
= 2.5 hours at 49 mph
<span> Check:</span>
58*3.5
= 203
49*2.5=
122.5
203+122.5
= 325.5
Answer:
the order is the option a. the smallest is T and the largest is S
