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3 years ago

ANSWER IF YOU KNOW!!!!! THANKS

Mathematics

2 answers:

Ad libitum [116K]3 years ago

6 0

Answer:

The third graph.

Step-by-step explanation:

The equations for the lines will be

P(x) = 2x-4

l(x) = -2x-4

When x = 0 both of these functions equal -4. The only graph where this happens is the third one.

You can check this by looking at the slopes and plugging in points.

balu736 [363]3 years ago

4 0

Answer:

It would be the third graph!

Step-by-step explanation:

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Put the following fractions in order from least to greatest, 1/8 2/5, 3/5, 1/6 1/4, 2/3, 1/3

Brut [27]

Answer:

Order from Least to Greatest

1/8 < 1/6 < 1/4 < 1/3 < 2/5 < 3/5 < 2/3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

PLEASE answer as soon as you can! First correct answer will get BRAINLIEST!!! :)

faltersainse [42]

(x+3)(x+5) would be the factoring of it

6 0

3 years ago

What is the fourth term in the binomial expansion of (2x – y) 7?

nata0808 [166]

Answer:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

Step-by-step explanation:

For this case we have the following expression:

$(2x-y)^7$

And we can use the binomial theorem given by:

$(x+y)^n =\sum_{k=0}^n (nCk) x^k y^{n-k}$

And for this case we want to find the fourth term and using the formula we have:

$(7C4) (2x)^4 (-y)^{7-4}$

And replacing we got:

$35 (2^4) x^4 (-y)^{-3}$

And then the final term would be:

$-560 x^4 y^3$

8 0

2 years ago

Mia is tracking her savings account balance . She knows the equation to find her balance y in any year t, but she can't remember

motikmotik

Complete question is;

Mia is tracking her savings account balance. She knows the equation y = 8000p^(t) can be used to find her balance y in any year t, but she can't remember what p represents. Her balance 3⅔ years after opening her account, is $9,905.54. What is the value of p?

Answer:

p = 1.06

Step-by-step explanation:

We are told that the equation y = 8000p^(t) can be used to find her balance y in any year t.

Now, we are given t = 3⅔ = 11/3 years

Also, we are given balance after 11/3 years as;

y = $9,905.54

Thus;

Plugging the relevant values into y = 8000p^(t), we have;

9,905.54 = 8000p^(11/3)

p^(11/3) = 9905.54/8000

p = (9905.54/8000)^(3/11)