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exis [7]
3 years ago
12

A population of mice has black or brown hair. The gene for black hair color (B) is dominant over brown (b). If 16% of the mice a

re homozygous black and 24% are heterozygous black, what would be the frequency of each allele?
(p + q = 1, p2 + 2pq + q2 = 1) A. p = 0.65, q = 0.35
B. p = 0.25, q = 0.75
C. p = 0.4, q = 0.6
Biology
2 answers:
Vadim26 [7]3 years ago
6 0
Ummmm I believe that the answer is C i'm not a hundred percent sure
IgorC [24]3 years ago
3 0

Answer:

yes the answer is C←←←←←←←←←←←←←←←←←←←←←←←←

Explanation:

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This solution has 80% solute concentration inside the cell, and 20% outside what is it?
KIM [24]

Answer:

surrounding solution

8 0
4 years ago
if you wanted to test red blood cells for their ability to complete glycolysis, what compound would you try to detect
Artemon [7]

Answer:

Pyruvate

Explanation:

Glycolysis refers to the pathway through glucose is oxidized to pyruvate.

In glycolysis, a molecule of glucose passes through ten enzyme catalyzed steps to yield two molecules of pyruvate.

Step 1: Glucose is phosphorylated to form glucose-6-phosphate

Step 2: Glucose-6-phosphate is converted to fructose-6-phosphate

Step 3: Fructose-6-phosphate is further phosphorylated to form fructose-1,6-bisphosphate

Step 4: Fructose-1,6-bisphosphate is cleaved into glyceraldehyde-3-phosphate and dihydroxyacetone phosphate

Step 5: Dihydroxyacetone phosphate is converted to another molecule of glyceraldehyde-3-phosphate.

Step 6: Two molecules of Glyceraldehyde-3-phosphate are converted to two molecules of 1,3-bisphosphoglycerate

Step 7: Two molecules of 1,3-bisphosphoglycerate are converted to 3-phosphoglycerate

Step 8: Two molecules of 3-phosphoglycerate are converted to two molecules of 2-phosphoglycerate

Step 9: Two molecules of 2-phosphoglycerate are converted to two molecules of phosphoenolpyruvate

Step 10: Two molecules of phosphoenolpyruvate are converted to two molecules of  pyruvate, the end-product of glycolysis.

Therefore, the presence of pyruvate molecules in red blood cells can be used to test for their ability to complete glycolysis

6 0
3 years ago
In the semiconversative replication of DNA, the DNA molecule formed consists of a all molecules with two new strands b all molec
Solnce55 [7]

Answer:

Option d. is correct

Explanation:

DNA stands for Deoxyribonucleic acid. It is the hereditary material found in all humans and almost all other organisms.

In the semiconversative replication of DNA, the DNA molecule formed consists of one-half of the molecules with two parental strands and one-half of the molecules with two new strands.

8 0
3 years ago
What term describes body parts of different organisms that are similar in form?
Alex777 [14]
Homologous Structures
4 0
3 years ago
the thompson seedless grape is triploid with three copies of each chromosome.Which phase of the cell cycle would you expect trip
max2010maxim [7]

The phase of the cell cycle one would expect triploid cells to be unable to complete would be Meiosis I.

<h3>Meiosis I</h3>

During meiosis I, homologous chromosomes pair up to form bivalents or tetrads. This means that for a triploid cell, one chromosome will not have a partner to pair with.

The existence of an unpaired chromosome after the pairing of homologous chromosomes will make the remaining processes of meiosis I likely impossible.

More on meiosis I can be found here: brainly.com/question/2095046?referrer=searchResults

5 0
3 years ago
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