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3 years ago

Please provide answers for the WHOLE page. It is only multiplication.

Mathematics

2 answers:

8_murik_8 [283]3 years ago

5 0

29. 1.08+.89+.89=2.86 they need 3 dollars
30.they need $3.34
31.each greeting card cost 35 cents
32. she does have enough money because it the total for 3 gift wraps is $5.55 which is less than $6

natka813 [3]3 years ago

4 0

29) Around 8 1+1+2+2+1+1
30) around 4
31)35 ceents
32)yes, each roll costs less than 2 dollars if you do $2 x 3 you get $6 but the rolls are less that $2 so she will have money to spare

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9. Sarah has to create a floral arrangement out of twigs and flowers that has a total of 9 objects. She has to

noname [10]

Answer:

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3 years ago

PLEASE HELP THIS IS URGENT!!!!

vichka [17]

Answer:

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3 years ago

14. Sharon earns $25 per item she sells plus a base salary of $100 per week. Write and solve an inequality to find how many item

kozerog [31]

Amount earned by Sharon per item sold = $25
Base salary of Sharon per week = $100
Amount that needs to be earned by Sharon per week = $700
Let us assume the number of items sold by Sharon per week = x
Then
100 + 25x = 700
25x = 700 - 100
25x = 600
x = 600/25
= 24
So Sharon needs to sell 24 items to earn a total of $700 per week. I hope you have understood the method of solving such problems.

8 0

4 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

Why do monkeys eat bananas?

Softa [21]

Answer:

because they are good ;)

Step-by-step explanation:

Monkeys like to eat bananas because these sweet fruits are found in the wild where primates live. Monkeys are omnivores that eat fruit, vegetables and foliage, not just bananas, according to the Great Ape Trust.

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3 years ago