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3 years ago

Can someone help please?

Mathematics

1 answer:

alina1380 [7]3 years ago

5 0

Answer:

(-1, 3)

Step-by-step explanation:

The given equation is 2x + y = 5.

Test whether (-1, 3) is a solution. To do this, substitute -1 for x and 3 for y. Does 2(-1) + 3 = 5? No, it does not. So this could be the correct answer choice.

Test whether (6, -7) is a solution. Is 2(6) - 7 = 5 true? Yes, it is. So this is not a correct choice.

Test whether (3, -1) is a solution. Is 2(3) -1 = 5? Yes, it is. So this is not a correct choice.

Summary: The only answer choice that does NOT satisfy the given equation is the first one: (-1, 3).

You might be interested in

The perimeter of the rectangle below is:

blondinia [14]

Answer:

18x + 28 is the perimeter

Step-by-step explanation:

As perimeter is the som of all side

So P = 6x+8 + 3x+6 + 6x+5 + 2x+2 + 3 + x+4

= 6x+3x+6x+2x+x + 8+6+5+2+3+4

= 18x + 28

5 0

2 years ago

Can someone help me please and explain.

exis [7]

[This question is such you will not understand a thing without your involvement as well. So follow my step and check by yourself]

First plot both functions on graph (this you gotta do yourself and check because only then you will learn)

How you plot the function?

f(x)=-3x³+5x-5

Put y=f(x)

y=-3x³+5x-5➡eqn(1)

So note the corresponding values of y on putting different values of x in that function.

I'll show u:

When x=0,y=-5 [calculate yourself it's easy just put x=0 and find value of y in eqn(1)]

Similarly,

x=1,y=-3

x=2,y=-19

[Similarly put x=-1,-2..and find corresponding y]

So you got points (0,-5),(1,-3),(2,-19)...plot these points and you have successfully plotted f(x).

Same process for plotting function g(x)....at least 6 points must be plotted.

❇After plotting f(x) and g(x):

1)check by yourself if they have same y-intercept (which is the distance between origin and the point of intersection of y-axis and the curve/line)

2) To check if they have same behavior or not,

increase the value of x[ie,1,2,3...] and note the corresponding value of y in function f(x) . Then decrease value of x[ie,-1,-2,-3..] and note corresponding value of y [note that y means function or f(x)]

Suppose f(x) has following end behavior:

When x increases f(x) tends to decrease

and when x decreases f(x) tends to increase

Now find end behavior of g(x) also..and if above end behavior matches with g(x), they will have same end behavior.

3) check by yourself by looking in plotted graphs of f(x) and g(x) whether they have at least one x-intercept or not.

4)g(x) is even function but f(x) is odd function.

So, g(x) is symmetrical over y-axis but f(x) is not.

5) Actually most of the algebraic polynomial functions don't show periodicity(but trigonometric and exponential function do). You can check by yourself by looking in plotted graph. If graph seems to be repeating same behavior it is periodic otherwise not. I am sure the given functions are not periodic. {Plz google periodic function if you want to know more}

3 0

3 years ago

Help if you’re good at math I’ll give brainliest

boyakko [2]

Answer:

(4,2)

Step-by-step explanation:

Just by looking at the graph, you can see that they intersect at (4,2). But just to check:

x - 2 = -0.5x + 4

1.5x = 6

x = 4

y = 4 - 2 = 2

(4,2)

6 0

3 years ago

Read 2 more answers

Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)

zubka84 [21]

$\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 
$

This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

$\frac{ \sqrt{-49}}{7-2i-4-9i}$

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result:

$\frac{ \sqrt{-49} }{3-11i}$

Now, the $\sqrt{-49}$ must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to $\sqrt{49} \sqrt{-1}$
This means that we get the result 7i for the numerator.

$\frac{7i}{3-11i}$

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: $x^2 - y^2 =(x+y)(x-y)$
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

$\frac{7i (3+11i)}{(3-11i)(3+11i)}$

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how $(3-11i)(3+11i)= 3^2 -(11i)^2$ therefore, we can finally write:

$\frac{7i(3+11i)}{3^2 - (11i)^2 }$

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product $7i(3+11i) = 21i+77i^2$ .
You should know from your classes that i^2 = -1, thefore the numerator simplifies to $-77+21i$
You can do it as a curious thing, but simplifying yields the result:
$\frac{-77+21i}{130}$

7 0

3 years ago

What is the sum of the negative integers greater than -5

uranmaximum [27]

-10= ( -4)+(-3)+(-2)+(-1)

7 0

3 years ago