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3 years ago

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At a little-know vacation spot, taxi fares are bargain. A 28 mile tail ride takes 32 minutes and cost $22.40. You want to find t

he cost of a 35 minute taxi ride. What unit price do you need

1 answer:

hram777 [196]3 years ago

5 0

I forgot How to do this Imao

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2 years ago

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My name is Ann [436]

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3 years ago

Write the equation of the line that fits the given conditions. 14. Parallel to 3x-2y=10 and passes through the point (2,2), Writ

trasher [3.6K]

Answer:

Step-by-step explanation:

Since the lines are parallel to each other that means they have the same gradient. So use the gradient formula y=mx+c where m is the gradient rearrange 3x-2y=10 using the formula to become -2y=-3x +10

divide both sides by -2 so that m=1.5. It passed through the point (2,2) use the equation of a line formula to find the the answer.

[{y - 2}/{x -2}=1.5

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hope that helps

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2 years ago

Lim as x--> 0 of (xcscx) is...

Serjik [45]

We know that:

limx→0 sin(x)/x = 1.
and
cscx = 1/sinx
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<span>limx→0 x/sinx = 1</span>

7 0

3 years ago

Kenny's scores the first 5 times he played a video game are listed below. 38, 51, 64, 77, 90 Kenny's scores follow a pattern. If

gayaneshka [121]

Kenny's score on his 72nd game played is 961

<em><u>Solution:</u></em>

Given that the first 5 score of Kenny are listed below:

38, 51, 64, 77, 90

Kenny's scores follow a pattern

<em><u>To find: Kenny's score on his 72nd game played</u></em>

Let us first find the pattern followed

38, 51, 64, 77, 90

<em><u>Find the difference between terms</u></em>

51 - 38 = 13

64 - 51 = 13

77 - 64 = 13

90 - 77 = 13

So the difference between terms is constant

So the sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>The formula for nth term of arithmetic sequence is given as:</u></em>

$a_n = a_1 + (n-1)d$

$a_n$ = the nᵗʰ term in the sequence

$a_1$ = the first term in the sequence

d = the common difference between terms

Here d = 13 and $a_1 = 38$

So we get,

$a_n = 38 + (n-1) \times 13$

<em><u>To find the score of 72nd game, substitute n = 72</u></em>

$a_{72} = 38 + (72-1) \times 13\\\\a_{72} = 38 + 71 \times 13\\\\a_{72} = 38 + 923\\\\a_{72} = 961$

Thus Kenny's score on his 72nd game played is 961

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2 years ago