Answer:
The 95% confidence interval for mean compressive strength is:
Step-by-step explanation:
We have a sample of n=12 specimens, with sample mean=3259.9 and sample standard deviation = 35.57.
We know the population is normally distributed.
For a 95% confidence interval and df=n-1=11, the t-statistic is t=2.201.
Then, the CI can be expressed as:
Answer:
8
Step-by-step explanation:
(5*2)+(2*5)-12=
10+10-12=
20-12=
8
Answer:
6.75
Step-by-step explanation:
2 crackers=5.50
1 cracker=5.50÷2
=2.25
3 crackers=2.25×3
=6.75
Answer:
The value of the second expression is 14, so the expressions are equivalent.
Step-by-step explanation:
x=5
6+2(5)-2=
6+10-2=
16-2=
14
The other expression also came out to be 14, so they are equivalent.
Answer:
<h2>The percentage of the people invited attended the fundraising event is <u>6</u><u>9</u><u>.</u><u>3</u><u>3</u><u>%</u>.</h2>
Step-by-step explanation:
To find the percentage of those who attended the fundraising event, simply divide the number of attendees to the total number invited.
