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laila [671]
3 years ago
9

What are the possible values of x in 8x^2+4x=-1

Mathematics
1 answer:
Vladimir79 [104]3 years ago
6 0

Answer:

x1=-0.25(+)(0.25i)

x2=-0.25(-)(0.25i)

Step-by-step explanation:

we have

8x^{2}+4x=-1

Factor the leading coefficient

8(x^{2}+0.5x)=-1

Complete the square. Remember to balance the equation by adding the same constants to each side.

8(x^{2}+0.5x+1/16)=-1+1/2

8(x^{2}+0.5x+1/16)=-1/2

(x^{2}+0.5x+1/16)=-1/16

Rewrite as perfect squares

(x+0.25)^{2}=-1/16

remember that

i=\sqrt{-1}

(x+0.25)=(+/-)(0.25i)

x=-0.25(+/-)(0.25i)

x1=-0.25(+)(0.25i)

x2=-0.25(-)(0.25i)

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A8 = 66 [8th term]

Step-by-step explanation:

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To find the 8th term. An nth term is where n is n in the sequence. So substitute 8 for n, and simplify.

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Step-by-step explanation:

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It said i need to simplify. how do i
horrorfan [7]

Answer:

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

The quantity of water per liter of flour = 1/3 liters

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Step-by-step explanation:

The given information from the graph are;

At 0 liters of water, the volume of flour = 0 liters of flour

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The equation for a linear relationship is y = m·x + c

m = The gradient or slope of the line, c = the y-intercept

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Such that when the question asks, how many liter of water is used per liter of flour, we get;

y = 1/3× 1 = 1/3 liters

Similarly when the question asks, how many liter of flour is used per liter of water, we get;

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