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9966 [12]
3 years ago
5

A class is organizing a going away party for one of their students. They spend $26.38 on decorations, $78.92 on food, and $34.50

on a gift. If there are 15 students in the class who agreed to split the cost evenly, then how much does each person owe?
Mathematics
1 answer:
Serjik [45]3 years ago
8 0

Answer:

$9.35

Step-by-step explanation:

Simply start by adding up the total cost of each item.

$26.38 + $78.92 + $34.50

= $140.25

The total is $140.25

If 15 students want to split the cost, you’ll need to divide it by 15.

$140.25 divided by 15 = $9.35

So the total for each student is $9.35

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A rancher wishes to build a fence to enclose a rectangular pen having area 24 square yards. Along one side the fence is to be ma
Gnoma [55]

Answer:

The  value  is  C \approx \$76

Step-by-step explanation:

From the question we are told that

   The  area of the rectangular pen is  A =  24 \ yard^2

     The  cost of material used to make one side is  z = \$ 6

    The  cost of material used to make the other sides is  r  =  \$ 3

Now  , the fence to be build around the rectangular pen  has four sides, the first opposite sides are equal, let assume each of the to be x yard   and the other opposite sides are also equal as well let assume of the to be y yard

So the cost is mathematically represented as

       C =  zx  +  r (x + 2y )

=>   C =  6x  +  3(x + 2y)

=>   C =   9x  +  6y

Now the area of the fence is mathematically represented as

      A =  x* y =  24

=>    y  =  \frac{24}{x}

=>  C =   9x  +  6[\frac{24}{x} ]

=>   C =   9x  +  [\frac{144}{x} ]

Now differentiating

     C'  =  9 + 144*  (-2) x^{-2}

     C'  =  9 - 288x^{-2}

At minimum C' =  0

So  

     9 - 288x^{-2} =  0

     x^{-2} =  0.03125

    x =  \sqrt{\frac{1}{0.03125} }

    x =  5.66

Now substituting for x in the equation above to obtain minimum cost

       C =   9(5.66)  +  [\frac{144}{5.66} ]

       C \approx \$76

   

 

8 0
3 years ago
When listing the domain (and range), we<br> list the repeated numbers
svetoff [14.1K]

Answer:hope help

Step-by-step explanation:

Find the range by listing all the y values from the ordered pairs. Repeated values within the domain or range don't have to be listed more than once. In order for a relation to be a function, each x must correspond with only one y value.

8 0
3 years ago
Read 2 more answers
True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (
PtichkaEL [24]

<u>answer (in words)</u>

FALSE. the coordinate pair (5, 2) is not a solution to the equation 2x+3y=10. in order to figure out whether or not the statement is true or false, plug the x and y values from the coordinate pair (5, 2) into the given equation, 2x+3y=10. if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

<em>(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)</em>

<u>answer (algebraic/steps for solving)</u>

first, plug in 5 for x in the equation 2x+3y=10.

  • 2x+3y=10 ⇒ 2(5)+3y=10

then plug in 2 for y.

  • 2(5)+3y=10 ⇒ 2(5)+3(2)=10

now your equation is 2(5)+3(2)=10. all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

  • 2(5)+3(2)=10 ⇒ 10 + 3(2) = 10

multiply 3 · 2.

  • 10 + 3(2) = 10 ⇒ 10 + 6 = 10

add 10 + 6.

  • 10 + 6 = 10 ⇒ 16=10

16 and 10 are <em>not</em> equal, therefore (5, 2) is not a solution to the equation 2x+3y=10. in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

6 0
3 years ago
Ricky can type 161 words in 7 minutes. how many can words can he type in 20 minutes.
kakasveta [241]
So 161 divide 7 equals 23 so therefor he types 23 words per minutes. 23 times 20 equals 460. I think he can type 460 words in 20 minutes.
8 0
3 years ago
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Each of the samples below is randomly selected from a company with 320 employees. Choose which samples are representative sample
morpeh [17]

Step-by-step explanation:

For all the recent strides we’ve made in the math world, like how a supercomputer finally solved the Sum of Three Cubes problem that puzzled mathematicians for 65 years, we’re forever crunching calculations in pursuit of deeper numerical knowledge. Some math problems have been challenging us for centuries, and while brain-busters like the ones that follow may seem impossible, someone is bound to solve ‘em eventually. Maybe.

For now, take a crack at the toughest math problems known to man, woman, and machine.

1. The Collatz Conjecture



DAVE LINKLETTER

Earlier this month, news broke of progress on this 82-year-old question, thanks to prolific mathematician Terence Tao. And while the story of Tao’s breakthrough is good news, the problem isn’t fully solved.

A refresher on the Collatz Conjecture: It’s all about that function f(n), shown above, which takes even numbers and cuts them in half, while odd numbers get tripled and then added to 1. Take any natural number, apply f, then apply f again and again. You eventually land on 1, for every number we’ve ever checked. The Conjecture is that this is true for all natural numbers.

Tao’s recent work is a near-solution to the Collatz Conjecture in some subtle ways. But his methods most likely can’t be adapted to yield a complete solution to the problem, as he subsequently explained. So we might be working on it for decades longer.

The Conjecture is in the math discipline known as Dynamical Systems, or the study of situations that change over time in semi-predictable ways. It looks like a simple, innocuous question, but that’s what makes it special. Why is such a basic question so hard to answer? It serves as a benchmark for our understanding; once we solve it, then we can proceed to much more complicated matters.

The study of dynamical systems could become more robust than anyone today could imagine. But we’ll need to solve the Collatz Conjecture for the subject to flourish.

6 0
3 years ago
Read 2 more answers
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