Question

I REALLY NEED HELP RIGHT NOW! T^TApplying the 30-60-90 Theorem, Solve this.​

Answer 1

Answer:

Step-by-step explanation:

take 30 degree as reference angle

using cos rule

cos 30=adjacent/hypotenuse

$\sqrt{3}$/2=7$\sqrt{3}$/y(do cross multiplication)

14$\sqrt{3$=y$\sqrt{3}$

14$\sqrt3}$/$\sqrt{3}$=y

14=y

for x

using pythagorsa theorem

H^2=P^2+B^2

14^2=X^2+(7$\sqrt{3}$)^2

196=X^2+147

196-147=X^2

49=X^2

$\sqrt{49}$=X

7=X