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3 years ago

I REALLY NEED HELP RIGHT NOW! T^TApplying the 30-60-90 Theorem, Solve this.

Mathematics

1 answer:

jarptica [38.1K]3 years ago

6 0

Answer:

Step-by-step explanation:

take 30 degree as reference angle

using cos rule

cos 30=adjacent/hypotenuse

$\sqrt{3}$ /2=7 $\sqrt{3}$ /y(do cross multiplication)

14 $\sqrt{3$ =y $\sqrt{3}$

14 $\sqrt3}$ / $\sqrt{3}$ =y

14=y

for x

using pythagorsa theorem

H^2=P^2+B^2

14^2=X^2+(7 $\sqrt{3}$ )^2

196=X^2+147

196-147=X^2

49=X^2

$\sqrt{49}$ =X

7=X

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Henry predicted whether he got answers right or wrong in his 50 question exam. He identified the 36 questions he thought he got

Paha777 [63]

Answer:

84%

Step-by-step explanation:

Henry completed a total of 50 questions. From these 50 he predicted 36 were right and this means he also predicted that 14 were wrong (50-36 = 14). From these predictions 5 out of 36 from the ones that he predicted were right were actually wrong and 3 of the 14 questions (14-11 = 3) he predicted were wrong were actually right. Meaning in total he wrongly predicted 8 questions which means he predicted 42 correctly ...

42 / 50 = 0.84 = 84%

Therefore, Henry's prediction accuracy is 84%

6 0

3 years ago

Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

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3 years ago

What is y-intercech of the function y = 2x^2 - 5x + 8

Oksanka [162]

Answer:

Step-by-step explanation:

The y intercept of a function is found by setting x equal to zero

y = 2x^2 - 5x + 8

y = 2*0 -5*0 +8

y = 8

The y intercept is 8

7 0

4 years ago

Miguel is a golfer, and he plays on the same course each week. The following table shows the probability distribution for his sc

aivan3 [116]

1) 4.55

2) Short hit

Step-by-step explanation:

The table containing the score and the relative probability of each score is:

Score 3 4 5 6 7

Probability 0.15 0.40 0.25 0.15 0.05

Here we call

X = Miguel's score on the Water Hole

The expected value of a certain variable X is given by:

$E(X)=\sum x_i p_i$

where

$x_i$ are all the possible values that the variable X can take

$p_i$ is the probability that $X=x_i$

Therefore in this problem, the expected value of MIguel's score is given by:

$E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55$

In this problem, we call:

X = Miguel's score on the Water Hole

Here we have that:

- If the long hit is successfull, the expected value of X is

$E(X)=4.2$

- Instead, if the long hit fails, the expected value of X is

$E(X)=5.4$

Here we also know that the probability of a successfull long hit is

$p(L)=0.4$

Which means that the probabilty of an unsuccessfull long hit is

$p(L^c)=1-p(L)=1-0.4=0.6$

Therefore, the expected value of X if Miguel chooses the long hit approach is:

$E(X)=p(L)\cdot 4.2 + p(L^C)\cdot 5.4 = 0.4\cdot 4.2 + 0.6\cdot 5.4 =4.92$

In part 1) of the problem, we saw that the expected value for the short hit was instead

$E(X)=4.55$

Since the expected value for X is lower (=better) for the short hit approach, we can say that the short hit approach is better.

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3 years ago

X^2 +4(x-1) > or equal to x^2+12

BARSIC [14]

X^2+4x-1>or equal tox^2+12
then the two x squared will cancel eachother which brings
4x-1>or equal to 12
the minus one goes to the other side then is added with 12
4x>or equal to 13
finally we divide both sides by four to get
x>or equal to 13/4

7 0

3 years ago

I REALLY NEED HELP RIGHT NOW! T^TApplying the 30-60-90 Theorem, Solve this.​

I REALLY NEED HELP RIGHT NOW! T^TApplying the 30-60-90 Theorem, Solve this.