What is 243.875 rounded to the nearest tenths on a number line

Jane wishes to have 20,000 available at the end of 10 years so she deposit money into an account that pays 1.14% compounded mont

max2010maxim [7]

Answer:

$\$17,846.12$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ A=\$20,000\\ r=0.0114\\n=12$

substitute in the formula above

$\$20,000=P(1+\frac{0.0114}{12})^{12*10}$

$P=\$20,000/[(1+\frac{0.0114}{12})^{120}]$

$P=\$17,846.12$

5 0

4 years ago

kyle walked his neighbors dog to earn money.He earned $89.49 during a 3 month period.What was the average amount kyle earned eac

lbvjy [14]

Jujiuhioooijjjhhjbhhh

4 0

3 years ago

Evaluate -4(12) please help

alex41 [277]

Answer:

You are going to get -48

Step-by-step explanation:

For some of the reason, this seemed like multiplication

But anyway, hope this helps, The other person Put down an answer that maybe is incorrect and they posted it like a file like they just don't care like a BOT

3 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$