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Travka [436]
2 years ago
11

Whats the pattern for this numbers 5, 3, 9, 2, 13

Mathematics
1 answer:
dimaraw [331]2 years ago
7 0

Step-by-step explanation:

Go and learn numbers , it will be 1 2 3 4 5

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What number when substituted for the variable, makes the equation 4/5x = 20 true?
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Drake rolls two fair number cubes. 1 2 3 4 5 6 1 1 2 3 4 5 6 2 2 4 6 8 10 12 3 3 6 9 12 15 18 4 4 8 12 16 20 24 5 5 10 15 20 25
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Wouldn’t it be 2/15 chance because there is only two fifteens
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The decimal d is formed by writing in succession all the positive integers in increasing order after the decimal point; that is,
Maksim231197 [3]

Answer:

2

Step-by-step explanation:

We are given that a decimal number  d

d=0.12345678...

Where d is formed by writing in succession all the positive integers in increasing order after decimal point.

We have to find the 100th digit of d to the right of the decimal point.

Place of first digit 1 after decimal=Tenth

Place of second digit 2 after decimal=Hundredth

Place of third digit  3 after decimal=Thousandth

Therefore, 100th digit of d to the right of the decimal point=2

5 0
3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
Mrs. Humble is filling bags with peanuts to give as gifts. Each bag will contain 1 and 3 over 4 pounds of peanuts. The peanuts c
DerKrebs [107]

Answer:

$8.75

Step-by-step explanation:

STEP TO TAKE TO DETERMINE THE ANSWER

Multiply 13/4 pounds by the cost of one pound of peanut. To do this, convert 13/4 to an improper fraction and then multiply it by $5

1\frac{3}{4} = \frac{7}{4}

\frac{7}{4} × 5 = \frac{35}{4} = 8\frac{3}{4} = $8.75

5 0
2 years ago
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