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olasank [31]
2 years ago
13

A town has a population of 5000 and grows at 3.5% every year. What will be the population after 15 years, to the nearest whole n

umber?
Mathematics
2 answers:
RUDIKE [14]2 years ago
5 0

Answer: 7,625

Step-by-step explanation:

polet [3.4K]2 years ago
5 0

Answer:

7625

Step-by-step explanation:

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What is 10% as a decimal?
DiKsa [7]
Hi there!

10% as a decimal is 0.1

To find the decimal of a percentage, just divide the percentage by 100.

10/100 = 1/10 = 0.1

I hope this helps!
6 0
3 years ago
All the information given in the photo, no idea how to solve <br>​
frosja888 [35]

Answer:

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Step-by-step explanation:

3 0
2 years ago
ANYONE FEEL LIKE THEY DON'T BELONG
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Answer:

all the time

Step-by-step explanation:

3 0
3 years ago
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What is the equation of a line that is perpendicular to the x-axis and passes through (3,-2)
34kurt

Answer:

x = 3

Step-by-step explanation:

we know that if we have an original line and we are finding the perpendicular we know that the slope of the second line is gonna be the negative reciprocal of the first line and given that we know it must be  perpendicular to the original line it will be heading downwards on the y axis with no slope so instead of y equals it will be x equals and we know that our x value of the point given is three so the answer is x = 3

4 0
3 years ago
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Suppose a population of deer in the state is 10, 289 and is growing 1% each year. Predict the population after 5 years
eimsori [14]

Answer: the population after 5 years is 10814

Step-by-step explanation:

The population growth of the deer is exponential. We would apply the formula for determining exponential growth which is expressed as

A = P(1 + r)^t

Where

A represents the population after t years.

n represents the period of growth

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 10289

r = 1% = 1/100 = 0.01,

t = 5 years

Therefore,

A = 10289(1 + 0.01)^5

A = 10289(1.01)^5

A = 10814

3 0
3 years ago
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