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Sholpan [36]
2 years ago
8

What is a noun and adjective

Mathematics
1 answer:
7nadin3 [17]2 years ago
8 0
Noun: A word that refers to something.

Adjective: A word that describes a trait.
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the table shows the pricing for four different types of gasoline which type cost the least per gallon a $20.20 for 10 galb $26.0
Ugo [173]

Answer:

A is the cheapest deal.

Step-by-step explanation:

find unit rate; cost / quantity

20.20 / 10 = $2.02 per gallon

26.04 / 12 = $2.17 per gallon

28.24 / 24 = $2.01 per gallon

30.45 / 25 = $2.03 per gallon

4 0
2 years ago
Find the value of x.<br> 110°<br> X + 116
LenKa [72]
Xterm correct answer is =11
7 0
2 years ago
How can complex fractions be used to solve problems involving ratios
strojnjashka [21]
When you have ratios, and some unknowns, you can create complex fractions from them. Bring them to the same denominator, and solve for x.

Example - we have this proportion:
2-x
5-45
And we can change it into fraction:
\frac{2}{5}=\frac{x}{45}

\frac{2*9}{5*9}=\frac{x}{45}

\frac{18}{45}=\frac{x}{45}
18=x

In case of more complex fractions it may come in handy.
5 0
3 years ago
A group of 100 people, some students, and some faculty attended a museum opening. Each student paid $10 per person for entrance
slava [35]

Answer: 80

Step-by-step explanation:

Let the number of students be represented by x

Let the number of faculty be represented by y.

Based on the information in the question, we can form an equation which will be:

x + y = 100 ..... i

10x + 25y = 1300 ....... ii

From equation i,

Make y the subject of the formula

y = 100 - x ...... iii

Put the value of equation iii into ii

10x + 25y = 1300

10x + 25(100 - x) = 1300

10x + 2500 - 25x = 1300

10x - 25x = 1300 - 2500

-15x = -1200

x = 1200/15

x = 80

There were 80 students who attended the museum opening

5 0
3 years ago
What is the solution to the equation below 5+6•log2 x=14
denis23 [38]
9514 1404 393
Answer:
2.83 for log2(x)
15.81 for log(2x)
Step-by-step explanation:
We can get the log function by itself by subtracting the constant and dividing by the coefficient.
5 +6·log2x = 14
6·log2x = 9 . . . . . . . subtract 5
log2x = 1.5 . . . . . . . divide by 6
At this point, we're not sure what is meant by log2x.
log₂(x) = 1.5 ⇒ x = 2^1.5 ≈ 2.83
log(2x) = 1.5 ⇒ x = (10^1.5)/2 ≈ 15.81
3 0
3 years ago
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