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4 years ago

-6h plus 4 - 3plus h equals 11

1 answer:

5 0

$- 6h + 4 - 3 + h = 11$
So we start by combining like terms;
$- 6h + h = - 5h$
$4 - 3 = 1$
Now we have;
$- 5h + 1 = 11$
We then subtract 1 from both sides;
$- 5h + 1 = 11$
$- 5h = 10$
Then we divide both sides by 5;
$- 5h = 10$
$- 5h \div - 5h = h$
$10 \div - 5h = - 2$
Leaving the final answer to be h = -2

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Help help I don’t really get this???

insens350 [35]

Answer:

Question 4: $y=\displaystyle -\frac{4}{5}x$

Question 5: $y=-5x-3$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope of the line and b is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

Question 4

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$ where two points that pass through the line are $(x_1,y_1)$ and $(x_2,y_2)$

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

$\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}$

Therefore, the slope of the line is $\displaystyle -\frac{4}{5}$ . Plug this into $y=mx+b$ as the slope (m):

$y=\displaystyle -\frac{4}{5}x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (b) is 0. Plug this into $y=\displaystyle -\frac{4}{5}x+b$ :

$y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x$

Question 5

1) Determine the slope (m)

$\displaystyle m=\frac{y_2-y_1}{x_2-x_1}$

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

$\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5$

Therefore, the slope is -5. Plug this into $y=mx+b$ :

$y=-5x+b$

2) Determine the y-intercept (b)

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (b) is -3. Plug this into $y=-5x+b$ :

$y=-5x+(-3)\\y=-5x-3$

I hope this helps!

8 0

3 years ago

Twice a number x exceed 5 at least by 4. find the possible value of x.

salantis [7]

Answer:

Step-by-step explanation:

2x › 5 (buy at least 4)

so you can just start plugging numbers in.

I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.

5 0

3 years ago

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-6y^2 + 9y^2 - y - 9 - 7y^2 + 1 + 10y + 3y

taurus [48]

Answer: -4y^(2)+12y-8

Step-by-step explanation: Combine like terms

6 0

3 years ago

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What is 46.78 - 18.55 estimate each sum of difference

Anastasy [175]

U estimate 46.78 to 47 and 18.55 to 19, so 47-19 is 28.

4 0

3 years ago

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What is an equation of the line that passes through the points (8,0) and (3,-5)?

slava [35]

Recall that the general equation for a line is y=mx+b where m is the slope and b is the y-intercept.
First, let's find the slope by finding
(y2-y1)/(x2-x1):
(-8-0)/(-5-3)
-8/-8
1

Now we know the equation is y=1x+b, or y=x+b.
By plugging in one of the two points we know is on the line, we can solve for b.
0=3+b
b=-3

So the equation is:
y=x-3

5 0

3 years ago

Read 2 more answers