Given:
μ = $3.26 million, averaged salary
σ = $1.2 million, standard deviation
n = 100, sample size.
Let x = random test value
We want to determine P(x>4).
Calculate z-score.
z = (x - μ)/ (σ/√n) = (4 - 3.26)/(1.2/10) = 6.1667
From standard tables,
P(z<6.1667) = 1
The area under the distribution curve = 1.
Therefore
P(z>6.1667) = 1 - P(z<=6.1667) = 1 - 1 = 0
Answer: The probability is 0.
What do you mean by that?
Answer:
68% Confidence interval = [4.5752, 4.5848]
95% Confidence interval = [4.5688, 4.5918]
Step-by-step explanation:
Sample mean (X) = 4.580
Sample Standard Deviation (S) = 0.01065
Sample size (n) = 6
for alpha/2 0.84 = 1.1037
for alpha/2 0.975 = 2.5706
68% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%5D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5752, 4.5848]
95% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5688, 4.5918]
Answer:
75
Step-by-step explanation:
Step 1
Matt is ordering basketball jerseys For his country's league. Last year he ordered 512 jerseys. 64 those jerseys were orange.
The ratio of all Jerseys to Jerseys that are Orange =
512 : 64
8 : 1
Step 2
If he ordered 600 jerseys this year, how many of them will be Orange if the ratio of orange jerseys to all the jerseys remain the same?
Since we are maintaining the ratio in step 1
Let the number of orange jerseys = x
600 : x = 8 : 1
Hence
600/x = 8/1
Cross Multiply
8 × x = 600 × 1
8x = 600
x = 600/8
x = 75
Therefore, this year, the number of orange jerseys = 75
