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3 years ago

Greater than 7 tens and less than 8 tens. The number has 4 ones

Mathematics

1 answer:

prohojiy [21]3 years ago

6 0

Answer is 74. Greater than 70 less than 80 so some where in the 70s. It has 4 ones so it would be 74.

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SOMEBODY GET IT RIGHT FOR ME PLS I NEED HELP ITS PYTHAGOREAN THEOREM

IrinaK [193]

Answer:

a^2+b^2=c^2

a^2=c^2-b^2

a^2=10^2-5^2

a^2=100-25

a^2=75

a=7.7cm

Step-by-step explanation:

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3 years ago

If your company needs to produce 7800 products by the end of the next 12 weeks how many products will you need to produce each w

Tomtit [17]

You have to do 7,800 divide by 12 and you get D) 650.

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4 years ago

Find the area of triangle ABC with vertices A(2,1), B (12,2), C (12,8). Hence, or otherwise find the perpendicular distance from

Lapatulllka [165]

<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$ </h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

$x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and y_3=8$

The area of a triangle is= $\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]$

= $|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|$

= $|-54|$ = 54 square units

The length of AC = $\sqrt{(x_1-x_3)^{2} +(y_1-y_3)^2}$

= $\sqrt{(2-12)^{2} +(1-8)^2}$

= $\sqrt{149}$ units

Let the perpendicular distance from B to AC be = x

According To Problem

$\frac{1}{2} \times x \times \sqrt{149} = 54$

⇔ $x =\frac{108}{\sqrt{149} }$ units

Therefore the perpendicular distance from B to AC is = $\frac{108}{\sqrt{149} } units$

5 0

3 years ago

Alvin's age is three times Elgas age. The sum of their ages is 36. What is Elgas age?

olchik [2.2K]

Answer:

Elgas is 9 years old.

Step-by-step explanation:

Alvin: 3 x Elgas

36: Alvin + Elgas

36 / 4 : 9

Elgas: 9

Alvin: 27

To check: 27 + 9= 36

3 0

3 years ago

Ammariah has finished 17/20 of her homework. How much more does she have to complete.

iren [92.7K]

Answer: A 15/100

Step-by-step explanation:

1. Convert 17/20 into percents

2. You get 85% Which is how much of her homework she has completed

3. To find what she has left subtract 85 from 100

4. You get 15 or 15/100 or 15% more of the test she hasn’t completed and needs to complete

8 0

3 years ago