This equation uses two properties of logarithms:
So you could take the ln from left and right hand side in the equation, and get:
(2-x)ln 3 = x ln 5
then
2 ln 3 - x ln 3 - x ln 5 = 0 =>
x(ln 3 + ln 5) = 2 ln 3
so x = 2 ln 3 / (ln3 + ln5)
Now using the 1st property you can say 2 ln 3 is ln 3² = ln9
and using the 2nd property you can say ln3 + ln5 = ln15
so x= ln9 / ln15
Answer:
the plans can go 560 miles per hour and in 10 hours it can travel 5600 miles
Step-by-step explanation:
1st divide miles over hour so you have to do 3360/6 and the solution you get for that equation is how far the plane can go in miles per hour 2nd for the second question you have to multiply your unit rate by the 10 hours so since our unit rate was 560 miles per hour you would multiply 360 and 10.
Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
U call it keep change change. keep 15.7. change it to subtract and change -3.45 to just 3.45 (positive not negative)
Step-by-step explanation:
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<u>Hope</u><u> it</u><u> helps</u><u>!</u>
