All categories

3 years ago

Solve the equation. (10x + 5) + (6x − 1) = 180 A. 9 B. 11 C. 17 D. 23

Mathematics

2 answers:

cluponka [151]3 years ago

3 0

(10x+5) + (6x-1)=180
10x+5+6x-1=180
16x+4=180
16x+4=180
16x=180-4
16x=178
x=11

otez555 [7]3 years ago

3 0

10 timea 5 is 50 6 take away 1 is 5 50 take away 5 is 45 71 take away 45 is 26 take away 3 is 23. So D is your answer

You might be interested in

A car depreciates in value by 17% per year.

otez555 [7]

Answer:

17%of 23000

17/100×23000

1 yrs depreciation is 3910

then

after 4 years depreciation is 4×3910

=15640

the worth of after 4 yrs is 23000-15640

=Rs 7360

7 0

3 years ago

For f(x) = 2x – 3 find f(-1/4)

Firdavs [7]

9514 1404 393

Answer:

-3 1/2

Step-by-step explanation:

Put the argument where the variable is and do the arithmetic.

f(-1/4) = 2(-1/4) -3 = -1/2 -3

f(-1/4) = -(3 1/2)

5 0

3 years ago

Giovanna has a score of

12345 [234]

Answer:'

-9.7 minus, in 13

Step-by-step explanation:

7 0

2 years ago

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

What is the absolute value of 19.8?

arsen [322]

Answer:

19 4/5

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers