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aleksley [76]
3 years ago
7

Solve the equation. (10x + 5) + (6x − 1) = 180 A. 9 B. 11 C. 17 D. 23

Mathematics
2 answers:
cluponka [151]3 years ago
3 0
(10x+5) + (6x-1)=180
10x+5+6x-1=180
16x+4=180
16x+4=180
16x=180-4
16x=178
x=11
otez555 [7]3 years ago
3 0
10 timea 5 is 50 6 take away 1 is 5 50 take away 5 is 45 71 take away 45 is 26 take away 3 is 23. So D is your answer
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The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

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5 7 12 16 18 24 12 and 16 are in the middle. Add 12 and 16 and then divide by 2 (28/2)= 14
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dimulka [17.4K]
Well using distance formula

d \:  =  \sqrt{(x {}^{2} }  - x {}^{1} ) + (y {}^{2}  + y {}^{1} )
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Equation 1:Ax+By=C Equation 2:Dx+Ey=F A, B, C, D, E, and F are non-zero real numbers. Which of the following could replace equat
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A, B and E.

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Check the picture below.

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