Recall the Pythagorean identity,
![1-\cos^2t=\sin^2t](https://tex.z-dn.net/?f=1-%5Ccos%5E2t%3D%5Csin%5E2t)
To get this expression in the fraction, multiply the numerator and denominator by
:
![\dfrac{t\sin t}{1-\cos t}\cdot\dfrac{1+\cos t}{1+\cos t}=\dfrac{t\sin t(1+\cos t)}{\sin^2t}=\dfrac{t(1+\cos t)}{\sin t}](https://tex.z-dn.net/?f=%5Cdfrac%7Bt%5Csin%20t%7D%7B1-%5Ccos%20t%7D%5Ccdot%5Cdfrac%7B1%2B%5Ccos%20t%7D%7B1%2B%5Ccos%20t%7D%3D%5Cdfrac%7Bt%5Csin%20t%281%2B%5Ccos%20t%29%7D%7B%5Csin%5E2t%7D%3D%5Cdfrac%7Bt%281%2B%5Ccos%20t%29%7D%7B%5Csin%20t%7D)
Now,
![\displaystyle\lim_{t\to0}\frac{t\sin t}{1-\cos t}=\lim_{t\to0}\frac t{\sin t}\cdot\lim_{t\to0}(1+\cos t)](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bt%5Cto0%7D%5Cfrac%7Bt%5Csin%20t%7D%7B1-%5Ccos%20t%7D%3D%5Clim_%7Bt%5Cto0%7D%5Cfrac%20t%7B%5Csin%20t%7D%5Ccdot%5Clim_%7Bt%5Cto0%7D%281%2B%5Ccos%20t%29)
The first limit is well-known and equal to 1, leaving us with
![\displaystyle\lim_{t\to0}(1+\cos t)=1+\cos0=\boxed{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bt%5Cto0%7D%281%2B%5Ccos%20t%29%3D1%2B%5Ccos0%3D%5Cboxed%7B2%7D)
The answer is C: Not likely, recurring debt is higher than what is allowed
Part A. B - Side MN
Side MN is directly parallel to side HK because, as shown by the graph, it is directly across from side HK.
Part B. B - 1/2
If you look at the width or length of the larger rectangle (the original), and compare that to the smaller, you can see that both the length and width of the larger rectangle are double the smaller rectangle.
Hope this helps!! :)
1. d-38
7. X= 3 1/2
8. 9
9. 2.28258488499
Can’t answer the rest but that what I can do
W = 14 •9
which means w= 14×9