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SIZIF [17.4K]
3 years ago
15

After just 4 tenths of a 2.5-mile race was completed, Lenox took the lead and remained there until the end of the race.

Mathematics
1 answer:
mixer [17]3 years ago
7 0

Answer:

Lenox lead the race is = 1.5 miles

Reid run without a cramp = 1.75 miles

Step-by-step explanation:

given data

Lenox lead race = \frac{4}{10}

total race = 2.5 mile = \frac{25}{10}

cramp = \frac{3}{10}

to find out

How many miles did Lenox lead the race and How many miles did Reid run without a cramp

solution

we know Lenox lead = \frac{4}{10}  and total race is 2.5 mile

so

Lenox lead the race is = \frac{4}{10}  of 2.5 mile

Lenox lead the race is = \frac{4}{10} × \frac{25}{10}

Lenox lead the race is = \frac{15}{10} = 1.5 miles

and

we know developed a cramp with  \frac{3}{10} of the race remaining

so

without cramp race is 1 - \frac{3}{10} = \frac{7}{10}

and run without cramp is \frac{7}{10} of 2.5 mile

Reid run without a cramp =  \frac{7}{10} × \frac{25}{10}

Reid run without a cramp =  \frac{175}{100}

Reid run without a cramp = 1.75 miles

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