Question

After just 4 tenths of a 2.5-mile race was completed, Lenox took the lead and remained there until the end of the race.

Answer 1

Answer:

Lenox lead the race is = 1.5 miles

Reid run without a cramp = 1.75 miles

Step-by-step explanation:

given data

Lenox lead race = $\frac{4}{10}$

total race = 2.5 mile = $\frac{25}{10}$

cramp = $\frac{3}{10}$

to find out

How many miles did Lenox lead the race and How many miles did Reid run without a cramp

solution

we know Lenox lead = $\frac{4}{10}$  and total race is 2.5 mile

so

Lenox lead the race is = $\frac{4}{10}$  of 2.5 mile

Lenox lead the race is = $\frac{4}{10}$ × $\frac{25}{10}$

Lenox lead the race is = $\frac{15}{10}$ = 1.5 miles

and

we know developed a cramp with  $\frac{3}{10}$ of the race remaining

so

without cramp race is 1 - $\frac{3}{10}$ = $\frac{7}{10}$

and run without cramp is $\frac{7}{10}$ of 2.5 mile

Reid run without a cramp =  $\frac{7}{10}$ × $\frac{25}{10}$

Reid run without a cramp =  $\frac{175}{100}$

Reid run without a cramp = 1.75 miles