Answer:
AAS, the two equal angles, the two right triangles, and the shared side
Step-by-step explanation:
Answer:
( 7 , 4 )
given:
make y the subject in equation 2:
4x - y = 24
-y = 24 - 4x
y = 4x - 24
insert this in equation 1:
4x + 10y = 68
4x + 10(4x - 24) = 68
4x + 40x - 240 = 68
44x = 68 + 240
44x = 308
x = 7
solve for y:
y = 4x - 24
y = 4(7) - 24
y = 4
Answer:
btw the pic is not loading and i am sure if you just listened to your teacher you would understand the question and it would not be so hard.
Step-by-step explanation:
Answer:
Step-by-step explanation:
a). Let the missing term = a
(a + 7) + (2x - 6) = -4x + 1
(a + 2x) + (7 - 6) = -4x + 1
(a + 2x) + 1 = -4x + 1
(a + 2x) = -4x
a = -4x - 2x
a = -6x
So the equation is,
(-6x + 7) + (2x - 6) = -4x + 1
b). (a² + p + 1) - (q + 5a + r) = 4a² -2a + 7
I have assumed p, q and r are the variables at the blank spaces.
(a² - q) + (p - 5a) + (1 - r) = 4a² - 2a + 7
By comparing both the sides of the equation,
a²- q = 4a²
q = a² - 4a²
q = -3a²
p - 5a = -2a
p = -2a + 5a
p = 3a
1 - r = 7
r = 1 - 7
r = -6
So the equation will be,
(a² + 3a + 1) - (-3a² + 5a - 6) = 4a²- 2a + 7
