Answer:
H0: μ ≤ 1.30
H1: μ > 1.30
|Test statistic | > 1.833 ; Reject H0
Test statistic = 3.11
Yes
Pvalue = 0.006
Step-by-step explanation:
H0: μ ≤ 1.30
H1: μ > 1.30
Samples, X ; 1.36,1.35,1.33, 1.66, 1.58, 1.32, 1.38, 1.42, 1.90, 1.54
Xbar = 14.84 / 10 = 1.484
Standard deviation, s = 0.187 (calculator)
Decison rule :
|Test statistic | > TCritical ; reject H0
df = n - 1 = 10 - 1 = 9
Tcritical(0.05; 9) = 1.833
|Test statistic | > 1.833 ; Reject H0
Test statistic :
(xbar - μ) ÷ (s/√(n))
(1.484 - 1.30) ÷ (0.187/√(10))
0.184 / 0.0591345
Test statistic = 3.11
Since ;
|Test statistic | > TCritical ; We reject H0 and conclude that water consumption has increased
Pvalue estimate using the Pvalue calculator :
Pvalue = 0.006
The value of f(-6) is -12.2
Explanation:
Given that the function 
We need to determine the value of f(-6)
The value of f(-6) can be determined by substituting the value for 
in the function and simplify the function.
Hence, let us substitute in the function, we get,
Let us apply the rule 
, we get,
Multiplying the numbers, we get,
The value of 
Substituting the value of , we get,
Subtracting the denominator, we have,
Dividing, we have,
Rounding off to the nearest tenth, we have,
Thus, the value of f(-6) is -12.2
Answer:
Step-by-step explanation:
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
area of rectangle= 8*13=104m^2
base of the Triangle= 13 -(4+4)=5
area of Triangle = 5*6/2=15m^2
area of shaded shape =104-15= 89m^2
9514 1404 393
Answer:
A. The equation represents a linear function because the equation is in the form y = mx + b
Step-by-step explanation:
A linear function does not have to be in the form y = mx + b, but if a function is in that form, it is a linear function.
choice A is appropriate
__
A function may have two variables, x and y, and not be a linear function. For example, y = x² is not a linear function. The fact that it has two variables is not what makes it linear.
