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ra1l [238]
3 years ago
9

Write 3 addition problems in which the fractions have denominators and the the sum is 1. Plz help with this.

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0
The answer will be fractions
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Subtraction of integers
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Answer:

First, keep the first number, Second, change the operation from subtraction to addition, Next, get the opposite sign of the second number (known as the subtrahend) and Lastly, proceed with the regular addition of integers.

Step-by-step explanation:

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3 years ago
21. 13/4 x 42/9 =<br> O<br> A. 132/18<br> B. 64/9<br> O<br> C. 77/18<br> D. 41/6<br> Worth 2 points
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Hi! 13/4 X 42/9 = 91/6 or 91/6 ls there any other options to choose from?
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3 years ago
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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Rzqust [24]

Answer:

a = 6 or 9

Step-by-step explanation:

The "a", "b", and "c" of the quadratic formula are the coefficients of a², a, and the constant term in the given equation:

... a = 2, b = -30, c = 108

Then the quadratic formula tells you the solutions are ...

... (-b ± √(b² -4ac))/(2a)

... = (-(-30) ± √((-30)² -4(2)(108)))/(2(2))

... = (30 ± √(900 -864))/4

... = (30 ± √36)/4

... = (30 ± 6)/4 = {24, 36}/4

... = {6, 9}

_____

The <em>a</em> variable should not be confused with the "a" that is used to name the coefficient of the square of the variable in the quadratic formula. If it is too confusing, rewrite one or the other. For example, you could write ...

... The solution to pa² +qa +r = 0 is ... a = (-q ± √(q²-4pr))/(2p)

where p=2, q=-30, r=108 in the given equation.

5 0
3 years ago
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