Given that the function is given by:
f(x)=2x+x
when x=3, then:
f(3)=2(3)+3
f(3)=6+3
f(3)=9
b] The zero of the function will be given by:
f(x)=2x+x=3x
When x=0 then f(x)=0, hence the zero of the function will be at x=0
No solutions
if you substitute the equations into each other the x's and y's will cancel each other out and you will be left with 9=-6 which isn't true<span />
3a, because both terms contain a, and 6 is divisible by 3
It would be f(t)= 25^t+1
If you plugged in '2' as 't',
25^2+1= 15, 625 which uses the second day of the bacteria.
