It is...........
2.789=2 ones and 7 tenths 8 hundreths 9 thousandths
X-6y=6 slope: 1/6 y-intercept (0,1)
X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
The equation showing this situation is 
Step-by-step explanation:
Given : A quadratic equation of the form 
has one real number solution.
To find : Which could be the equation?
Solution :
A quadratic equation in form 
has a solution 
called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.
Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :
1) If 
there are two real roots.
2) If there are one real roots.
3) If 
there are no real roots.
According to question,
A quadratic equation of the form has one real number solution.
So, The equation showing this situation is
