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Gelneren [198K]
3 years ago
14

there are 12 students working in the library. If 3/4 of them are girls, how many girls are working in the library?

Mathematics
2 answers:
Inga [223]3 years ago
6 0
There are 9 girls working in the library.
kolezko [41]3 years ago
6 0
\text {Total number of students = 12}

\text {Number of girls = }  \dfrac{3}{4}  \text { of the students}

\text {Number of girls = }  \dfrac{3}{4}  \times 12

\text {Number of girls = }  \dfrac{3}{4}  \times  \dfrac{12}{1}

\text {Number of girls = } 9

--------------------------------------------------------
Answer: There are 9 girls in the library.
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sveta [45]
Part A:
y=mx+b
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Part B:
621=83(7)+b
621=581+b
621-581=b
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Insurance cost is 40$


6 0
3 years ago
Question 2 - Signal and System Properties. State whether each of the statements is true or false. Note that a statement is true
gregori [183]

Answer:

  (a) true

  (b) true

  (c) false; {y = x, t < 1; y = 2x, t ≥ 1}

  (d) false; y = 200x for .005 < |x| < 1

Step-by-step explanation:

(a)  "s(t) is periodic with period T" means s(t) = s(t+nT) for any integer n. Since values of n may be of the form n = 2m for any integer m, then this also means ...

  s(t) = s(t +2mt) = s(t +m(2T)) . . . for any integer m

This equation matches the form of a function periodic with period 2T.

__

(b) A system being linear means the output for the sum of two inputs is the sum of the outputs from the separate inputs:

  s(a) +s(b) = s(a+b) . . . . definition of linear function

Then if a=b, you have

  2s(a) = s(2a)

__

(c) The output from a time-shifted input will only be the time-shifted output of the unshifted input if the system is time-invariant. The problem conditions here don't require that. A system can be "linear continuous time" and still be time-varying.

__

(d) A restriction on an input magnitude does not mean the same restriction applies to the output magnitude. The system may have gain, for example.

6 0
4 years ago
08.06)Data are collected about the amount of time, in minutes, each member of a dance troupe spend practicing. How does a single
Tpy6a [65]

The <em>correct answer</em> is:


A single outlier causes the value of the median to move slightly toward the outlier.


Explanation:


Overall, outliers have very little effect on the median. However, they do affect it some.


If the outlier is a very large number, the median will slightly increase as compared to the data set without the outlier.


If the outlier is very small, the median will slightly decrease compared to the data set without the outlier.


In both instances, the median is moved slightly towards the outlier.

8 0
3 years ago
Find the exact value of cot 330° in simplest form with a rational denominator.
Hoochie [10]

Answer:

\cot 330^{\circ} = -\sqrt{3}

Step-by-step explanation:

The cotangent function can be rewritten by trigonometric relations, that is:

\cot 330^{\circ} = \frac{1}{\tan 330^{\circ}} = \frac{\cos 330^{\circ}}{\sin 330^{\circ}} (1)

By taking approach the periodicity properties of the cosine and sine function (both functions have a period of 360°), we use the following equivalencies:

\sin 330^{\circ} = \sin (-30^{\circ}) = -\sin 30^{\circ} (2)

\cos 330^{\circ} = \cos (-30^{\circ}) = \cos 30^{\circ} (3)

By (2) and (3) in (1), we have following expression:

\cot 330^{\circ} = -\frac{\cos 30^{\circ}}{\sin 30^{\circ}}

If we know that \sin 30^{\circ} = \frac{1}{2} and \cos 30^{\circ} = \frac{\sqrt{3}}{2}, then the result of the trigonometric expression is:

\cot 330^{\circ} = -\frac{\frac{\sqrt{3}}{2} }{\frac{1}{2} }

\cot 330^{\circ} = -\sqrt{3}

6 0
3 years ago
Write the prime factorization of 132 using exponents.
Aleksandr [31]
132=2*66=2*2*33=2*2*3*11=2²*3*11
7 0
3 years ago
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