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Oduvanchick [21]

3 years ago

15

Which of the following relations is a function? A. { (1, 2), (1, 3), (1, 4), (1, 5) } B. { (1, 3), (2, 3), (4, 3), (9, 3) } C. {

(5, 4), (-6, 5), (4, 5), (4, 0) } D. { (6, -1), (1, 4), (2, 3), (6, 1) }

1 answer:

PtichkaEL [24]3 years ago

4 0

The answer would be B

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Owen makes $3,000 per month. He spends $300 on credit card payments and $350 on an auto loan. What is his debt-to-income ratio?

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Find the slopes of the asymptotes of the hyperbola with the following equation.

frosja888 [35]

You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36

36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
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3 years ago

What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success p? C

charle [14.2K]

Answer:

$(D)E[ X ] =np.$

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success p,

$f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq x\leq n$

$E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}$

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

$E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}$

Now,

$x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)$

Substituting,

$E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}$

Factoring out the n and one p from the above expression:

$E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}$

Representing k=x-1 in the above gives us:

$E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}$

This can then be written by the Binomial Formula as:

$E[ X ] = (np) (p +(1 - p))^{n -1 }= np.$

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3 years ago

Lara wants to inscribe a square in a circle using only a compass and straightedge. She will first construct a circle and locate

Mamont248 [21]

In Step 2, Lara did not ensure that the second diamter was perpendicualr to the first diameter she drew.

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Step 2: Draw a second diameter <em>perpendicular to the first diameter</em>. Label the points at which the second diameter touches the circle as C and D.

Step 3: Join the end points of the two diameters to form a square.

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Marysya12 [62]

Answer:

I think slope-intercept

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