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2 years ago

3(m - 1) = 5m +3 -2m please help me solve this step by step asap!

Mathematics

1 answer:

cupoosta [38]2 years ago

3 0

Answer:

0 = 6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(m−1)=5m+3−2m

(3)(m)+(3)(−1)=5m+3+−2m (Distribute)

3m+−3=5m+3+−2m

3m−3=(5m+−2m)+(3) (Combine Like Terms)

3m−3=3m+3

Step 2: Subtract 3m from both sides.

3m−3−3m=3m+3−3m

−3=3

Step 3: Add 3 to both sides.

−3+3=3+3

0=6

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2 years ago

A digital rain gauge has an outdoor sensor that collects rainfall and transmits data to an indoor display. Assume you produced a

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Answer:

a. A continuous graph

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c. The graph consists of three straight lines attached end to end, with the first segment being an inclined positively sloped graph, the second segment is an horizontal line while the third segment is a gentle positively sloped straight line

Step-by-step explanation:

a. A continuous graph

Given that the rain gauge is a digital rain gauge, the values transmitted to the indoor display are those collected by the outdoor sensor, we have that the output to the transmitter can be any value within a possible and finite range of values, therefore the graph is continuous

b. Whereby it rained at a constant rate of 0.1 inch per hour over 24-hour period, we have;

i) Whereby the graph is the level of water in the rain gauge over a given period of time, the shape of the graph will be a straight line graph with a gentle positive slope of 0.1 the domain will be from 0 to 24 hours, while the range will be from 0 to 2.4 inches

c) i) Given that i) the rain falls at a constant rate of 0.1 inch per hour for 6 hours, and ii) over the next 6 hours it stops raining, after which iii) it rained 0.2 inch for the next 12 hours, we have;

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3 years ago

Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s

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Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.

Then we have $n_{1} = 25$ , $\bar{x}_{1} = 2.04$ , $\sigma_{1} = 0.010$ and $n_{2} = 20$ , $\bar{x}_{2} = 2.07$ , $\sigma_{2} = 0.015$ . The pooled estimate is given by

$\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552$

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative).

The test statistic is $T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}}$ and the observed value is $t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257$ . T has a Student's t distribution with 20 + 25 - 2 = 43 df.

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$-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}$

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2 years ago

Find slope please help asap

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3 years ago

Read 2 more answers

Two cylindrical containers, C and D, with different capacities are shown below. What is the total volume of liquid held in these

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Answer:

Option D. (x + 4)(x + 1)

Step-by-step explanation:

From the question given above, the following data were obtained:

C = (6x + 2) L

D = (3x² + 6x + 9) L

Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:

Volume in C = ½C

Volume in C = ½(6x + 2)

Volume in C = (3x + 1) L

Volume in D = ⅓D

Volume in D = ⅓(3x² + 6x + 9)

Volume in D = (x² + 2x + 3) L

Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:

Volume in C = (3x + 1) L

Volume in D = (x² + 2x + 3) L

Total volume =?

Total volume = Volume in C + Volume in D

Total volume = (3x + 1) + (x² + 2x + 3)

= 3x + 1 + x² + 2x + 3

= x² + 5x + 4

Factorise

x² + 5x + 4

x² + x + 4x + 4

x(x + 1) + 4(x + 1)

(x + 4)(x + 1)

Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.

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3 years ago