It would be: 63 / 28 = 9 / 4
So, your answer is 9/4
Hope it helped.
Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.
F=9/5c+32
-31=9/5c+32
-63=9/5c
-35=c
Step-by-step explanation:
what is the main condition the lengths of the sides of a right-angled triangle have to fulfill ?
Pythagoras !
c² = a² + b²
c is the Hypotenuse (the baseline opposite of the 90 degree angle), a and b are the so-called legs (the sides enclosing the 90 degree angle).
only if there is a combination of the sides, for which the Pythagoras equation is true, do we have a right-angled triangle. otherwise not.
we also know CA = 18 - 7 - 3 = 8 cm
so, let's try
8² = 7² + 3²
64 = 49 + 9 = 58 wrong
7² = 8² + 3²
49 = 64 + 9 = 73 wrong
3² = 8² + 7²
9 = 64 + 49 = 113 wrong
so, there is no combination, where the Pythagoras equation is true, so it is NOT a right-angled triangle.
