Ask question

Ask question

All categories

3 years ago

5

Which could be the side lengths of a right triangle?

2 answers:

Vsevolod [243]3 years ago

5 0

Answer:

B

Step-by-step explanation:

90+45+45=180

All triangles equal 180.

Its B because if one angle is 90° then the other angles will equal each other. It cant be 60° and 30° because they dont equal, so your final answer is B.

Hope this Helps!!! :)

algol133 years ago

3 0

The correct answer is B

You might be interested in

What is the value of P(B')?

Butoxors [25]

Answer: ) Events A and B are such that: P(A) = 0.4; P(B) = 0.5; P(A n B) = 0.3; and P(A u B) = 0.6. i) What is the value of P(A u B')? (Where B' is the compliment of B.) 0.

Step-by-step explanation: I just did a little extra credit :D

6 0

3 years ago

3x +. 5g - 2g + 3x<br> Ajebra

Vladimir79 [104]

Answer:

try these two 6x - 1.5g or 6x + 1.5g

3 0

3 years ago

12. At the movie theater, they give out a free drink to every 75th customer and a free bag of popcorn to every 30th customer. Wh

Romashka [77]

Answer:

150th customer

Step-by-step explanation:

To find this we would need the lcm lowest common factor of 30 and 75

LCM 30 = 2,5,3,1

LCM 75 = 3,5,5

H.C.F = 2,3,5,5

= 150

the 150th custome would be getting both gift.

7 0

3 years ago

Through which pairs of points is the slope negative? Select all that apply.

horsena [70]

Answer:

The answer is C and D

3 0

4 years ago

A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he

Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

$h(t) = -16t^2 + 30t$

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

$f(x) = ax^2 + bx + c$ :

$f(\frac{-b}{2a}) = maximum/minimum$

i.e we first solve for $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for x in $f(x) = ax^2 + bx + c$

In our case:

First we need to solve $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for t in $h(t) = -16t^2 + 30t$

By comparison:

$b = 30$

$c = -16$

$\frac{-b}{2a} = \frac{-30}{2 * -16}$

$\frac{-b}{2a} = \frac{-30}{-32}$

$\frac{-b}{2a} = \frac{30}{32}$

$\frac{-b}{2a} = \frac{15}{16}$

Substitute $\frac{15}{16}$ for t in $h(t) = -16t^2 + 30t$

$h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})$

$h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}$

$h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}$

$h(\frac{15}{16}) = \frac{-225 + 450}{16}$

$h(\frac{15}{16}) = \frac{225}{16}$

$h(\frac{15}{16}) = 14.0625$

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because $14.0625 < 15$

8 0

3 years ago