The buffer will probably be destroyed by the addition of HCN.
<h3>What is buffer solution?</h3>
A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.
Given that a 1.0 l buffer solution is 0.15 m in HCN and 0.10 m in NaCN.
We need to find a action which one destroy the buffer solution.
A buffer is a substance made of salt and a weak acid that is beneficial. From the aforementioned chemicals, HCN is a potent acid and NaCN is a salt between HF and NaCN. Therefore, the buffer will probably be destroyed by the addition of HCN.
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I also worked it out but I got -5/3
2(6p-5) ≥ 3(p-8) -1
12p-10 ≥ 3p-24-1
12p-10 ≥ 3p-25
12p-3p ≥ -25+10
9p ≥ -15
-15/9
P ≥ -5/3
The solution of the quadratic equation is x = 0 or x = 6 ⇒ 4th answer
Step-by-step explanation:
The form of the quadratic equation is ax² + bx + c = 0, where
- a is the coefficient of x²
- b is the coefficient of x
- c is the numerical term
The quadratic equations has two roots, to find them factorize it into two factors and equate each factor by zero
∵ 3x = 0.5 x²
- Subtract 3x from both sides
∴ 0 = 0.5x² - 3x
- Multiply both sides by 2 to make the coefficient of x² integer
∴ 0 = x² - 6x
- Switch the two sides
∴ x² - 6x = 0
- Factorize it by taking x as a common factor
∴ x(x - 6) = 0
- Equate each factor by 0
∴ x = 0 → 1st root
∴ x - 6 = 0
- Add 6 to both sides
∴ x = 6 → 2nd root
∴ The roots of the equation are 0 or 6
The solution of the quadratic equation is x = 0 or x = 6
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