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Alexandra [31]
3 years ago
6

A _______ is made by placing two inclined planes back to back

Mathematics
2 answers:
mylen [45]3 years ago
5 0
A wedge is made by placing two inclined planes back to back
Andru [333]3 years ago
4 0
A wedge is two inclined planes placed back to back
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Fatima is shading this model to show 0.08x3 . shade the correct amount of boxes that will show the product
Karo-lina-s [1.5K]
Shade 0.08 3 times

In total that's 24 hundreths to shade


For more help, please upload a picture

Hope this helps!!
7 0
3 years ago
Kite GHIJ has sides GH, HI, IJ and JG. What are the diagonals of this figure? Select all that apply.
juin [17]

Answer:

  GI or HJ

Step-by-step explanation:

Diagonals connect non-adjacent vertices.

That is, the diagonal with G as an endpoint will not connect to vertices H or J, but will connect to vertex I. Likewise the diagonal with H as one end will have J as the other end. A quadrilateral has only two (2) diagonals. Of course, each can be named two ways:

 GI or IG

 HJ or JH

6 0
3 years ago
If a human face only have 2 eye balls how many eye balls can rap there whole head? 1-10 in why?
IceJOKER [234]
22 I hope this helps
7 0
3 years ago
One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p
scZoUnD [109]

Answer:

c^2 = 9dp

Step-by-step explanation:

Given

dx^2 + cx + p = 0

Let the roots be \alpha and \beta

So:

\alpha = 2\beta

Required

Determine the relationship between d, c and p

dx^2 + cx + p = 0

Divide through by d

\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0

x^2 + \frac{c}{d}x + \frac{p}{d} = 0

A quadratic equation has the form:

x^2 - (\alpha + \beta)x + \alpha \beta = 0

So:

x^2 - (2\beta+ \beta)x + \beta*\beta = 0

x^2 - (3\beta)x + \beta^2 = 0

So, we have:

\frac{c}{d} = -3\beta -- (1)

and

\frac{p}{d} = \beta^2 -- (2)

Make \beta the subject in (1)

\frac{c}{d} = -3\beta

\beta = -\frac{c}{3d}

Substitute \beta = -\frac{c}{3d} in (2)

\frac{p}{d} = (-\frac{c}{3d})^2

\frac{p}{d} = \frac{c^2}{9d^2}

Multiply both sides by d

d * \frac{p}{d} = \frac{c^2}{9d^2}*d

p = \frac{c^2}{9d}

Cross Multiply

9dp = c^2

or

c^2 = 9dp

Hence, the relationship between d, c and p is: c^2 = 9dp

8 0
3 years ago
Please help me solve this
Brilliant_brown [7]

Answer:

the answer will be something like 18

4 0
3 years ago
Read 2 more answers
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