Answer: what is the problem
Step-by-step explanation:
Answer:
1 hot dog costs $0.75
1 bratwurst costs $1.35
Step-by-step explanation:
Let x and y be the price per dozen of hot dogs and bratwursts respectively.
The first day they sold 8 dozen hot dogs and 13 dozen bratwursts for $282.60
8x + 13y = 282.60
The second day they sold 10 dozen hot dogs and 15 dozen bratwursts for a total of $333.00
10x + 15y = 333
and we have the linear system
<em>8x + 13y = 282.60
</em>
<em>10x + 15y = 333
</em>
which can be written in matrix form as
The solution would be given by
We have
hence
Now,
if a dozen hot dogs cost $9, 1 hot dog costs 9/12 = $0.75
if a dozen bratwursts cost $16.2, 1 bratwurst costs 16.2/12 = $1.35
Answer:
fsdfd
Step-by-step explanation:
Hmmm lemme do the first one only
Answer:
a. 720
b. 0.3
Step-by-step explanation:
a.
Three balls are selected at random without replacement.
First ball can be selected in 10 ways
Second ball can be selected in 9 ways
Third ball can be selected in 8 ways
Thus, there are 10×9×8 =720 different ways of selecting three balls.
b.
There are three cases that satisfy this condition
- first ball picked is 5, the others are not
- first ball is not 5, second is 5, third is not
- first and second ball is not five, third ball is 5
Each probabilities are:



Thus, one of the balls selected is the number 5 is then 