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MArishka [77]
3 years ago
7

3n-2(n+8)=-8 please show work

Mathematics
2 answers:
pshichka [43]3 years ago
7 0

Answer:

n=8

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3n−2(n+8)=−8

3n+(−2)(n)+(−2)(8)=−8(Distribute)

3n+−2n+−16=−8

(3n+−2n)+(−16)=−8(Combine Like Terms)

n+−16=−8

n−16=−8

Step 2: Add 16 to both sides.

n−16+16=−8+16

n=8

serg [7]3 years ago
4 0

Answer:

n = 8

Step-by-step explanation:

3n - 2(n + 8) =  - 8

3n - 2n - 16 =  - 8

n - 16 =  - 8

n =  - 8 + 16

n = 8

#IfWrongPleaseReport

#StudyTogetherWithMe

#ILoveMath

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What is the division of 6/11? Like how do you solve it with the work.
GREYUIT [131]

Answer

0.5454...

Step-by-step explanation:

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11⟌60000

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3 0
3 years ago
Please help me best answer gets brainliest
tia_tia [17]
I’m this you should know that it is best to find the area of each triangle then add them together

As you see the base is 24 so you take half of 24 for the base of your triangles and you get 12

1/2 is one half

TRIANGLE A

A = 1/2( Base (times) height)
A = 1/2(12 (times) 35) = 210

The formula will be the exact same for the other triangle.

When adding the areas up you get 420 squared inches.

Therefore answering is 420 in^2
7 0
3 years ago
I need some help plzz
Alika [10]
D seems to be right answer
3 0
3 years ago
Read 2 more answers
Hope you can see it please help!! Thanks
gavmur [86]

8x -12 = 4x


4x = 12


x =3

5 0
4 years ago
Read 2 more answers
The​ quality-control manager at a compact fluorescent light bulb​ (CFL) factory needs to determine whether the mean life of a la
Taya2010 [7]

Answer:

The mean life of a large shipment of CFL bulbs is equal to 7,520 hours.

Step-by-step explanation:

The quality control manager wants to determine whether the mean life of a large shipment of CFL bulbs is equal to 7,520 hours.

The quality control manager can use a one-sample test to determine whether the mean life is 7,520 hours or not.

The hypothesis can be defined as follows:

<em>H₀</em>: The mean life of a large shipment of CFL bulbs is equal to 7,520 hours, i.e. <em>μ</em> = 7520.

<em>Hₐ</em>: The mean life of a large shipment of CFL bulbs is different from 7,520 hours, i.e. <em>μ</em> ≠ 7520.

The information provided is:

\sigma=1200\\n=64\\\bar x=7324

As the population standard deviation is provided, we will use a <em>z</em>-test for single mean.

Compute the test statistic value as follows:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{7324-7520}{1200/\sqrt{64}}=-1.31

The test statistic value is -1.31.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the <em>p</em>-value for the two-tailed test as follows:

p-value=2\times P(Z

*Use a <em>z</em>-table for the probability.

The <em>p</em>-value of the test is 0.1902.

The <em>p</em>-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, it can be concluded that the mean life of a large shipment of CFL bulbs is equal to 7520 hours.

4 0
3 years ago
Read 2 more answers
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