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Simora [160]
3 years ago
11

Add 3 level scoops of mini chocolate chips and 1 level scoop of raisins to Container 1. If each scoop has the same number of ite

ms, what percent of the items in Container 1 are mini chocolate chips? (This value is known as the percent concentration of chips.) Explain how you decided. Label the container appropriately Answer: 50% because when there is only 2 variables and they are each 1 cup there is an even amount of stuff and when you ask for only one percentage that would be 50% because everything is even. Even if you asked for the percentage for the cup of raisins it would also be 50% Add 2 scoops of mini chocolate chips and 3 scoops of raisins to Container 2. What is the percent concentration of mini chocolate chips? Explain how you decided. Label the container appropriately. Stir the chips and raisins in each container to ensure that the chips and raisins are evenly mixed.
Mathematics
1 answer:
myrzilka [38]3 years ago
7 0

Answer:

Container 1  

The percentage of mini chocolate chip is 3/4 * 100= 75 % to raisins.

Container 2

The percentage of mini chocolate chip is 2/5 * 100= 40 % to raisins.

Step-by-step explanation:

Container 1  

Mini Chocolate Chips:  Raisins

3 scoops: 1 scoop

The percentage of mini chocolate chip is 3/4 * 100= 75 % to raisins.

Container 2

Mini Chocolate Chips:  Raisins

2 scoops: 3 scoop

The percentage of mini chocolate chip is 2/5 * 100= 40 % to raisins.

This is simplified with the help of the ratios . We find out the ratio of the mini chocolate to the total of both the ratios and mulitply it with 100 to get the percentage concentration.

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2x+2y/2w+3z
2(-5)+2(8)/2(-2)+3(-3)
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8 0
3 years ago
Simplify the exponential expression.
olga_2 [115]

The solution for the expression (v²)(m⁴)/(v²)(m³) will be m. The correct option is C.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The given expression will be solved as below:-

E =  (v²)(m⁴)/(v²)(m³)

Divide v² by the same term v².

E = (m⁴)/(m³)

E = m

Therefore, the solution for the expression (v²)(m⁴)/(v²)(m³) will be m. The correct option is C.

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8 0
2 years ago
In Friday NIght Funkin' dave and bambi How and What did Dave become 3D?
Ierofanga [76]

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Step-by-step explanation:

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2 years ago
In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct
kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

                  =(0.93\times0.03)+(0.10\times0.97)\\=0.1249

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

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What’s the answer to m/-3 + 10 = 11
Ira Lisetskai [31]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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