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The mass of April and her bumper car is 80 kg
Explanation:
This problem can be solved by using the law of conservation of momentum.
In fact, the total momentum of the system must be conserved before and after the collision, so we have:
where:
is the mass of Fiona+her bumper
is the initial velocity of Fiona (we take her direction as positive direction)
is the final velocity of Fiona (she rebounds back)
is the mass of April+her bumper
is the initial velocity of April (in the opposite direction)
is the final velocity of April
Re-arranging the equation, we can find the mass of April+bumper:
![m_2 = \frac{m_1 u_1 - m_1 v_1}{v_2-u_2}=\frac{(80)(3)-(80)(-1)}{3-(-1)}=80 kg](https://tex.z-dn.net/?f=m_2%20%3D%20%5Cfrac%7Bm_1%20u_1%20-%20m_1%20v_1%7D%7Bv_2-u_2%7D%3D%5Cfrac%7B%2880%29%283%29-%2880%29%28-1%29%7D%7B3-%28-1%29%7D%3D80%20kg)
Learn more about momentum here:
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When we see glass, we don't see the glass object itself but through other objects in the room are reflected/distorted by the glass. The glass disappeared because both Pyrex and vegetable oil bend (refract) light by the same amount – light travels straight through both materials!
- In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
- In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
<h3>How to achieve the desired resistance under these circumstances?</h3>
In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:
R₃ = 20 + Rt
R₃ = 20 + 25
R₃ = 45 Ohms.
<h3>Part B.</h3>
In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.
1/Rt = 1/R₁ + 1/R₂
1/Rt = 1/50 + 1/50
1/Rt = 2/50
1/Rt = 1/25
Rt = 25 Ohms.
1/R't = 1/R₁ + 1/R₂
1/R't = 1/20 + 1/20
1/R't = 2/20
1/R't = 1/10
R't = 10 Ohms.
Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:
R₃ = 10 + Rt
R₃ = 10 + 25
R₃ = 35 Ohms.
Read more on resistors in parallel here: brainly.com/question/15121871
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Complete Question:
You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.
(a) How can the desired resistance be achieved under these circumstances?
(b) What can you do if you need a 35-ω resistor?