The sphere’s Electric potential energy is 1.6*
J
Given,
q=6. 5 µc, V=240 v,
We know that sphere’s Electric potential energy(E) = qV=6.5*
=1.6*J
<h3>Electric potential energy</h3>
The configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.
In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."
A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?
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The dimension of force, F is ML/T².
<h3>What is force?</h3>
Force is a push o push agent which causes a change in the state of rest or motion of an object.
From a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass.
Mathematically; acceleration ∝ F/m
F = ma
dimension of Mass = M
dimension of acceleration = L/T²
dimension of force, F = ML/T²
In conclusion, the dimension of force is obtained from the dimensions of mass and acceleration.
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Answer: He would reach 7m/s at the distance of 17,5m.
Explanation: In order for us to know how long it takes for the speed to be reached, we use the equation V= Vo + at, with V=7m/s, Vo= 0m/s since you start from rest and a=1.4m/s². T is the time in seconds that we want to find out.
7 = 0 + 1.4t
7 = 1.4t
t= 5s
Now, we want to know the distance this boy reaches in 5 seconds, in a 7m/s speed and accelarating in 1.4m/s². For finding this out, we use another equation, S = So + Vot + (at²)/2, S being the final distance, So = 0m because he started from rest, and the other variables used before.
S = 0 + 0*5 + [1.4*(5²)]/2
S = 0 + 0 + (1.4*25)/2
S = 35/2
S = 17,5m
