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wolverine [178]
4 years ago
6

Express each of these statements using quantifiers. Then form the negation of the statement so that no negation is to the left o

f a quantifier. Next, express the negation in simple English. (Do not simply use the phrase "It is not the case that.")a) All dogs have fleas.b) There exists a horse that can add.c) Every koala can climb.d) No monkey can speak French.
e) There exists a pig that can swim and catch fish.
Mathematics
1 answer:
oksian1 [2.3K]4 years ago
4 0

Answer:

a) All dogs have fleas.

X the set of all animals

D(y)=y is a dog

F(y)=y has fleas

∀X ( D(x) → F(x) )

¬∃X ( D(x) ^ F(x) )

b) There exists a horse that can add.

X the set of all animals

H(y)=y is a horse

A(y)=y can add

∃X ( H(x) ^ A(x) )

∀X ( H(x) → ¬A(x) )

c) Every koala can climb.

X the set of all animals

K(y)=y is a koala

C(y)=y can climb

∀X ( K(x) → C(x) )

¬∃X ( K(x) ^ C(x) )

d) No monkey can speak French.

X the set of all animals

M(y)=y is a Monkey

F(y)=y can speak French

∀X ( M(x) → ¬F(x) )

∃X ( M(x) ^ F(x) )

e) There exists a pig that can swim and catch fish.

X the set of all animals

P(y)=y is a pig

S(y)=y can swim

C(y)=y can catch fish

∃X ( P(x) ^ ( S(x) ^ C(x) )

∀X ( P(x) → ( ¬S(x) v ¬C(x) ) )

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Answer:

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Answer:

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3 years ago
There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d
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<u>Given</u>:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

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<u>Probability</u>:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is P(B)=\frac{3}{10}

The probability of selecting a white marble without replacement is P(W)=\frac{2}{9}

The probability of selecting a black marble and then a white marble without replacement is given by

P(B \ and \ W)=P(B) \cdot P(W)

Substituting the values, we get;

P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}

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P(B \ and \ W)=\frac{1}{15}

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Answer:

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Step-by-step explanation:

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Assuming the top of the hill is 0.

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Hope this helps!! :)

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