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hoa [83]
3 years ago
10

There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d

rawn, find P(black and then white) *
Mathematics
1 answer:
stich3 [128]3 years ago
4 0

<u>Given</u>:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

The marbles are selected by not replacing the drawn ones.

We need to the probability of selected a black marble and then a white marble without replacement.

<u>Probability</u>:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is P(B)=\frac{3}{10}

The probability of selecting a white marble without replacement is P(W)=\frac{2}{9}

The probability of selecting a black marble and then a white marble without replacement is given by

P(B \ and \ W)=P(B) \cdot P(W)

Substituting the values, we get;

P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}

P(B \ and \ W)=\frac{6}{90}

P(B \ and \ W)=\frac{1}{15}

Thus, the probability of selecting a black marble and then a white marble without replacement is \frac{1}{15}

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The question is the second difference the answer box covered it up
Naily [24]

Answer:

The second difference, let suppose denoted by d₂, can be obtained by taking the difference between consecutive terms of the first difference of y-values, such as:

  • d₂ = 3 - 1 = 2
  • d₂ = 5 - 3 = 2

Step-by-step explanation:

Given the table

x                    y

0                   3

1                    4

2                   7

3                   12

The (first) difference, let suppose denoted by d, of y values can be obtained  by taking the difference between consecutive terms.

  • d = 4 - 3 = 1
  • d = 7 - 4 = 3
  • d = 12 - 7 = 5

The second difference, let suppose denoted by d₂, can be obtained by taking the difference between consecutive terms of the first difference of y-values, such as:

  • d₂ = 3 - 1 = 2
  • d₂ = 5 - 3 = 2
8 0
3 years ago
Can you help me solve systems of equations by elimination step by step<br> 6x+y=15<br> -7x-2y=-10
Anna71 [15]

Answer:   (4, -9)

<u>Step-by-step explanation:</u>

Use elimination method.  Manipulate one (or both) equations to eliminate one of the variables and solve for the remaining variable.  <em>I will be eliminating y</em>

6x +  y =  15    → 2(6x +  y =  15)   →   12x + 2y = 30

-7x - 2y = -10   → 1(-7x + 2y = -10)   →  <u> -7x - 2y = -10</u>

                                                             5x        = 20

                                                               x         =  4

Next, replace "x" with "4" into either equation and solve for y.

6(4) + y = 15

24  + y = 15

         y  = -9


<u>Check:</u>

Plug in x = 4 and y = -9 into the other equation to verify it makes a true statement.

-7x - 2y = -10

-7(4) - 2(-9) = -10

-28  -   -18  = -10

-28  +  18 = -10

       -10    =  -10  \checkmark

6 0
4 years ago
Solve the equation using the quadratic formula. X^2-9x+3=0
Nesterboy [21]

Answer:

The answer is x= \frac{9+\sqrt{69}}{2}, x= \frac{9-\sqrt{69}}{2}

Step-by-step explanation:

x^2=a

-9x=b

3=c

Plug into formula.

Equation: \frac{9+-\sqrt{(-9)^2-4(1)(3)}}{2}

Simplify the equation.

Equation: \frac{9+-\sqrt{81-12}}{2}

Subtract 81 and 12.

Equation: \frac{9+-\sqrt{69}}{2}

Spit into two equations

Equation 1: \frac{9+\sqrt{69}}{2}

Equation 2: \frac{9-\sqrt{69}}{2}

Hope this helps!

8 0
3 years ago
William has a 26-liter glass tank. First, he wants to put some marbles in it, all of the same volume. Then, he wants to fill the
Lilit [14]

The volume of the marbles is   26-20.9 = 5.1 l      and there ar e85 marbles

5.1/85 = .06 l/marble

 

then 200 marbles would requrie    .06 l/marble x 200 marbles = 12 liters

so he would only need  26-12= 14 liters of water to fill the tank !

7 0
3 years ago
Read 2 more answers
2x+3x^2(4x-5)<br> please helpppp asap
Aliun [14]

Here's my step-by-step explanation:

We're just gonna factor.

If your teacher has spoken of FOIL, then he/she has probably said that it means First Outer Inner Last and that it helps with distributing problems like these.

Right, so let's get to it.

2x+3x^2 (4x-5)\\2x(4x-5)+3x^2(4x-5)\\2x(4x) + 2x(-5) + 3x^2(4x) + 3x^2(-5)

Can you see the FOIL method being spread out here? Let's keep going.

2x(4x) + 2x(-5) + 3x^2(4x) + 3x^2(-5)\\8x^2 + (-10x) + 12x^3 + (-15x^2)\\12x^3 + 8x^2 - 15x^2 -10x\\12x^3 -7x^2 -10x

Hope this helps, and let me know if I made a mistake! ^_^

7 0
3 years ago
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