For this case, the first thing we must do is find the multiples of the coefficients.
We have then:
- <em>42: 1, 2, 3, 6, 7, 14, 21, 42
</em>
- <em>56: 1, 2, 7, 8, 28, 56
</em>
We observe that the biggest common factor is given by 7.
Therefore, by rewriting the expression we have:

Answer:
An equivalent expression is given by:

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Pic below on how I did it
The answer is 3 bozo open ur eyes
Answer: A) 71.498 ; b) 0.00152
Step-by-step explanation:
Given the following :
Number of atoms that decayed during 365 days period = 26,097
Number of days = 365
Mean number of radioactive atoms that decayed in a day:
Mean = number of decayed atoms / number rof days
Mean = 26,097 / 365
Mean = 71.498 atoms per day
B.) probability that 50 radioactive atoms decayed in a given day:
Using the poisson distribution formula :
P(x =x) = (m^x * e^-m) ÷ x!
Where m = mean
Mean (m) = 71.498
P(x = 50) = (71.498^50 * e^-71.498) / 50!
P(x = 50) = (71.498^50 * 2.7182818^-71.498) / 50!
= 4.60795E61 / 50!
= 0.0015150
Step-by-step explanation:
We can make 2 equations as follows:
2x = y + 16 and x + 2y = 18
x + 2y = 18 is the same as x = 18 - 2y. Hence, 2(18 - 2y) = 2x = y + 16.
2(18 - 2y) = y + 16
36 - 4y = y + 16
5y = 20
y = 4.