3 years ago

If the hypotenus is 41 inches, and one of the legs is 40 inches what is the length of the other Leg

1 answer:

7 0

You find the answer through the Pythagorean theorem

a^2 + b^2 = c^2 a & b are the legs and c is the hypotenuse
a = 40
b = ?
c = 41

40^2 + b^2 = 41^2
1600 + b^2 = 1681
b^2 = 1681 - 1600
b^2 = 81
b = 9

the length of the other leg is 9

i hope you found this helpful!

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