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podryga [215]
3 years ago
9

If the hypotenus is 41 inches, and one of the legs is 40 inches what is the length of the other Leg

Mathematics
1 answer:
andre [41]3 years ago
7 0
You find the answer through the Pythagorean theorem

a^2 + b^2 = c^2 a & b are the legs and c is the hypotenuse
a = 40
b = ?
c = 41

40^2 + b^2 = 41^2
1600 + b^2 = 1681
b^2 = 1681 - 1600
b^2 = 81
b = 9

the length of the other leg is 9

i hope you found this helpful!
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Please solve in the next 10 minutes pleaseeee
Alex787 [66]

Answer:

43.82 mph

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Step-by-step explanation:

Given :

S = √30fl

S = speed of car

f = drag Coefficient

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If f = 0.8 ; l = 80 feets

s = √30fl

s = √(30*0.8*80)

s = √1920

s = 43.817

s = 43.82 mph

B.)

s = 80 mph

f = 0.8

s = √30fl

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80 = √24l

Square both sides

80² = 24l

6400 = 24l

l = 6400/24

l = 266.67 feets

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Rina8888 [55]

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4.255 ft²

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Solve for x: -4x - 12 < 12
aliina [53]

Seems like you are an imposter ;). This is Middle School math.

Anyways...

Answer:

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