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3 years ago

You send 40 text messages in one month. The total cost is $4.80. How much does each text message cos

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

I hope this helps you

grandymaker [24]3 years ago

5 0

Should be 0.12 just divide 40 and 4.80. To double check it 0.12 times 40.

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A jet plane carry up to 200,000 liters of fuel. It used 130,000 of fuel during the flight what is the %

S_A_V [24]

Answer:

65%

Step-by-step explanation:

Given that,

Total fuel = 200000 L

Used fuel = 130,000 L

We need to find the percentage of the used fuel. It can be given by :

$\%=\dfrac{130,000}{200000}\times 100\\\\=65\%$

So, the required percentage is 65%.

8 0

2 years ago

Algebra 1 A Adaptive CR (JL22) 1/Tools Of The Trade

Archy [21]

The simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$

Expressions raise to power 0 is 1.

So, we have:

$(4^3)(\frac{4^4x^4}{3^2x^2y^2})$

Apply the law of indices to expression with common base

$(\frac{4^{4+3}x^{4-2}}{3^2y^2})$

Evaluate the sum and difference

$(\frac{4^7x^2}{3^2y^2})$

Remove the bracket

$\frac{4^7x^2}{3^2y^2}$

Hence, the simplified expression of $(4^3)(\frac{4^4^0x^4}{3^2x^2y^2})$ is $\frac{4^7x^2}{3^2y^2}$

Read more about exponents at:

brainly.com/question/847241

#SPJ1

8 0

1 year ago

-25 Points-

Elden [556K]

Answer:

(x+1)^2+(y+1)^2=13

Step-by-step explanation:

Equation of a circle: (x – h)^2 + (y – k)^2 = r^2

center: (-1, -1)

radius: sqrt(6^2+4^2)/2=sqrt(52)/2=2sqrt(13)/2=sqrt(13)

Substitute those values in to get

(x+1)^2+(y+1)^2=13

7 0

3 years ago

Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x

mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;