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ANEK [815]
3 years ago
10

Find the 63rd term of the arithmetic sequence: 10, 7, 4, 1, , …

Mathematics
2 answers:
dsp733 years ago
8 0

Answer:

the nth term is -3n+13.

so if you substitute n for 63, the answer would be -176

Step-by-step explanation:

tino4ka555 [31]3 years ago
6 0

Answer: the 63rd term is - 176

Step-by-step explanation:

In an arithmetic sequence, consecutive terms differ by a common difference.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 10

d = 7 - 10 = 4 - 7 = 1 - 4 = - 3

n = 63

We want to determine the value of the 63rd term, T63. Therefore,

T63 = 10 + (63 - 1) × - 3

T63 = 10 - 186 = - 176

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Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

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this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

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