The list price of a set of golf clubs is $399.99. If the series discount offered is 20/20/15, find the net cost after trade disc
1 answer:
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Step-by-step explanation:
1. Create your own example and explain how to solve Quadratic Equation using Quadratic Formula.
The quadratic formula is used to solve quadratic equations. It is shown as
A quadratic equation is generally shown in the form of
For example, if you saw the equation
7 would be , 3 would be
, and 20 would be
.
To solve the equation above, you would fill in the quadratic formula as such,
Then you could solve for x.
2. What part in the Quadratic Formula is the discriminant?
The discriminant is the equation under the square root on the quadratic formula,
It is tells us whether there are two solutions, one solutions, or no solutions.
3. How do you know the number of solutions based on the value of the discriminant?
To know the number of solutions based off of the value of the discriminant, you need to plug in your values. Using the example quadratic equation,
We will plug the values into the discriminant.
Now, if the discriminant is positive it has two real solutions. If the discriminant is zero the equation has no real-number solutions. And finally, if the discriminant is negative, the equation has one real solution. Because our discriminant is -551, the example equation has one real solution.
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Answer:
The answer is below
Step-by-step explanation:
Given that:
The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:
a) For x < 2:
From normal distribution table, P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%
b) For x = 2:
For x = 11:
From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337
c) For x = 11:
From normal distribution table, P(x < 11) = P(z < 1.67) = 0.9525
d) For x = 2:
For x = 5:
From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) = 0.2033- 0.0188 = 0.1845
e) For x = 5:
From normal distribution table, P(x < 5) = P(z < -0.83) = 0.2033