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sweet-ann [11.9K]
3 years ago
5

Anyone know the answer?

Mathematics
1 answer:
Ne4ueva [31]3 years ago
7 0

Answer:

?

Step-by-step explanation:

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PLEASE HELP!!!!!!!!!!!!!!!!!!!! THIS IS DUE TODAY
NeTakaya

Answer:

G) $3.60

Step-by-step explanation:

First, we need to find the unit rate of the 6 pounds of tomatoes Harry bought.

Unit rate: cost/unit

Unit rate: $4.32/6 lbs. ⇒ $0.72

This means a pound of tomatoes costs $0.72.

Now that we know the unit rate, we can find the total cost that Connie paid for 5 pounds of tomatoes.

0.72(5) = $3.60

Therefore, the correct answer is G) $3.60.

Hope this helps!

4 0
2 years ago
Identify the vertex and y-intercept of the graph of the function y = (x + 2) − 3. Use the drop-down menus to show your answer.
shepuryov [24]

Answer:

Was the function typed incorrectly?  Should it be y = (x + 2)^{2} - 3?

Step-by-step explanation:

8 0
2 years ago
A person drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 200 times. Here are the observed f
Alona [7]

Solution :

The objective of the study is to test the claim that the loaded die behaves at a different way than a fair die.

Null hypothesis, $H_0:p_1=p_1=p_3=p_4=p_5=p_6=\frac{1}{6}$

That is the loaded die behaves as a fair die.

Alternative hypothesis, $H_a$ : loaded die behave differently than the fair die.

Number of attempts , n = 200

Expected frequency, $E_i=np_i$

                                        $=200 \times \frac{1}{6} = 33.333$

Test statistics, $x^2= \sum^6_{i=1} \frac{(O_i-E_i)^2}{E_i} $

                            $=\frac{(28-33.333)^2}{33.333}+\frac{(29-33.333)^2}{33.333}+\frac{(40-33.333)^2}{33.333}+\frac{(41-33.333)^2}{33.333}+\frac{(28-33.333)^2}{33.333}+$$\frac{(34-33.333)^2}{33.333}$

≈ 5.8

Degrees of freedom, df = n - 1

                                       = 6 - 1

                                       = 5

Level of significance, α = 0.10

At α = 0.10 with df = 5, the critical value from the chi square table

$x^2_{\alpha}= \text{chi inv}(0.10,5)$

     = 9.236

Thus the critical value is $x_{\alpha}^2=9.236$

$P \text{ value} = P[x^2_{df} \geq x^2]$

             $=P[x^2_5\geq 5.80]$

             = chi dist (5.80, 5)

             = 0.3262

Decision : The value of test statistics 5.80 is not greater than the critical value 9.236, thus fail to reject $H_o$ at 10% LOS.

Conclusion : There is no enough evidence to support the claim that the loaded die behave in a different than a fair die.

3 0
3 years ago
What is the decimal equivalent of Two-sixths?<br><br> 0.3<br> 0.3<br> 0.6<br> 0.6
andrezito [222]
The answer is correct answer is b
3 0
3 years ago
This table shows the number of cars that a local car dealership sold each week for the past five weeks.
xeze [42]

Answer:

it affects the mean because it doesn't affect the mode neither the median so it's the mean

5 0
3 years ago
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