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alina1380 [7]
3 years ago
8

The two dot plots represent a sample of the number of

Mathematics
2 answers:
zheka24 [161]3 years ago
8 0

The answer is:

Both have the same number of data points

Both means are between 3 and 4

Westwood has less variability than Middleton

Anon25 [30]3 years ago
7 0

Answer:

The right anwers are : A B and E

Step-by-step explanation:

right on edg!

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Which equation can be used to solve X in the following diagram?
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The length of the hypotenuse of a 30-60-90 triangle is 28 m. Find the length of the side opposite the 30 angle
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<span>In a 30°-60°-90° triangle, the hypotenuse (c) is twice the length of the shorter leg (a) which is the opposite to the 30 angle:
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c = 2a


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The average full-time faculty member in a college works an average of 53 hours per week. a) If we assume the standard deviation
arsen [322]

Answer:

2.28% of faculty members work more than 58.6 hours a week.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The average full-time faculty member in a college works an average of 53 hours per week. Standard deviation of 2.8 hours.

This means that \mu = 53, \sigma = 2.8

What percentage of faculty members work more than 58.6 hours a week?

The proportion is 1 subtracted by the p-value of Z when X = 58.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{58.6 - 53}{2.8}

Z = 2

Z = 2 has a p-value of 0.9772

1 - 0.9772 = 0.0228

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2.28% of faculty members work more than 58.6 hours a week.

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