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3 years ago

Which graph shows the solution set of the inequality 2.9(x+8) <26.1?

Mathematics

2 answers:

andrezito [222]3 years ago

8 0

Answer:

Step-by-step explanation:

trust me bro

alekssr [168]3 years ago

3 0

9514 1404 393

Answer:

Step-by-step explanation:

The inequality symbol is < (not ≤), which means the end point of the graph will be an open circle.

After dividing by the coefficient of x, you have an inequality of the form ...

x +( ) < ( )

which means <em>the solution will be left of the (open circle) end point</em> of the graph. Only one graph has that form.

If you actually work through the numbers, you get ...

x +8 < 9 . . . . . . divide both sides by 2.9

x < 1 . . . . . . . . . subtract 8 from both sides

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Answer:

The 4th option

Step-by-step explanation:

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What is the value of y in the equation 5x+2y=20, when x=0.3

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3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

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Which expression is equivalent to (^5sqrt3^2)^1/3

11Alexandr11 [23.1K]

Answer:

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Step-by-step explanation:

(^5sqrt3^2)^1/3

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