X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
The area of a trapezoid if found using the formula
A = (base1 + base2)/2 x height
Area = (3+5)/2 x 1.5
Area = 8/2 x 1.5
Area = 4 x 1.5
Area = 6 square feet.
