Colin gets 3/10 , emma and dave 7/10 (ratio 3:2) %287%2F10%29%2F5+=+7%2F50%29
emma 21/50 and Dave 14/50 0r 7/25 of the money
Answer:
Description
Step-by-step explanation:
1. Factor 2x^2+11x+12 -> (2x+3)(x+4)
x=-4, -3/2
Both numbers are rational numbers as both can be expressed in the form in a quotient with integer values.
2. If discriminant is negative, then solutions are imaginary, meaning that the discriminant is less than 0, so you can set up this equation.
11^2 - 4(a)(12) < 0
121 - 48a < 0
a>121/48
The closest integer to 121/48 (~2.52) such that it satisfies the above conditions is 3, so the lowest value for a is 3.
Change the wording a bit, and type in your answer.
You should try to retake the picture can’t c anything
1 Convert
5
2
3
5
3
2
to improper fraction. Use this rule:
a
b
c
=
a
c
+
b
c
a
c
b
=
c
ac+b
5
×
3
+
2
3
−
3
3
4
=
1
+
2
3
+
3
4
3
5×3+2
−3
4
3
=1+
3
2
+
4
3
2 Simplify
5
×
3
5×3 to
1
5
15
1
5
+
2
3
−
3
3
4
=
1
+
2
3
+
3
4
3
15+2
−3
4
3
=1+
3
2
+
4
3
3 Simplify
1
5
+
2
15+2 to
1
7
17
1
7
3
−
3
3
4
=
1
+
2
3
+
3
4
3
17
−3
4
3
=1+
3
2
+
4
3
4 Convert
3
3
4
3
4
3
to improper fraction. Use this rule:
a
b
c
=
a
c
+
b
c
a
c
b
=
c
ac+b
1
7
3
−
3
×
4
+
3
4
=
1
+
2
3
+
3
4
3
17
−
4
3×4+3
=1+
3
2
+
4
3
5 Simplify
3
×
4
3×4 to
1
2
12
1
7
3
−
1
2
+
3
4
=
1
+
2
3
+
3
4
3
17
−
4
12+3
=1+
3
2
+
4
3
6 Simplify
1
2
+
3
12+3 to
1
5
15
1
7
3
−
1
5
4
=
1
+
2
3
+
3
4
3
17
−
4
15
=1+
3
2
+
4
3
7 Find the Least Common Denominator (LCD) of
1
7
3
,
1
5
4
3
17
,
4
15
Method 1: By Listing Multiples
List out all multiples of each denominator, and find the first common one.
Multiples of 3 : 3, 6, 9, 12, ...
Multiples of 4 : 4, 8, 12, ...
Therefore, the LCD is
1
2
12.
Method 2: By Prime Factors
List all prime factors of each denominator, and find the union of these primes.
Prime Factors of 3 : 3
Prime Factors of 4 : 2, 2
Therefore, the LCD is
2
×
2
×
3
=
1
2
2×2×3=12.
I believe is the second one on first picture(starts with (-2,1) and ends with (7,4)
