The rectangle shown as a perimeter of 70 cm and the given area. It’s length is 8 more than twice it’s width. Write and solve a s
ystem of equations to find the dimensions of the rectangle.
The length of the rectangle is ___cm and the width of the rectangle is ___cm.
The length of the rectangle is ___cm and the width of the rectangle is ___cm.
1 answer:
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9514 1404 393
Answer:
c. 1150 square units
Step-by-step explanation:
The sum of the two side lengths is half the perimeter, so is 125/2 = 62.5 units. The long side is 4/5 of that, so is 50 units.
The area is the product of the long side and the height to the long side:
A = bh
A = (50 units)(23 units) = 1150 units²
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<em>Additional comment</em>
This geometry is impossible, because the height from the long side cannot be more than the length of the short side. Here, the short side is 12.5 units, so it is not possible for the height to be 23 units.
If the height is measured from the short side, then the area is 287.5 square units.
